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aleksandr82
4 days ago
5

If the axes of the two cylinders are parallel, but displaced from each other by a distance d, determine the resulting electric f

ield in the region R>R3, where the radial distance R is measured from the metal cylinder's axis. Assume d<(R2−R1). Express your answer in terms of the variables ρE, R1, R2, R3, d, R, and appropriate constants.
Physics
1 answer:
serg [3.2K]4 days ago
6 0

Response:

E =  ρ ( R1²) / 2 ∈o R

Clarification:

Provided information

Two cylinders are aligned parallel

Distance = d

Radial distance = R

d < (R2−R1)

To determine

Express the response using the variables ρE, R1, R2, R3, d, R, and constants

Solution

We have two parallel cylinders

therefore, area equals 2 \pi R × l

And we apply Gauss's Law

EA = Q(enclosed) / ∈o......1

Initially, we calculate Q(enclosed) = ρ Volume

Q(enclosed) = ρ ( \pi R1² × l )

Thus, inserting all values into equation 1

produces

EA = Q(enclosed) / ∈o

E(2 \pi R × l)  = ρ ( \pi R1² × l ) / ∈o

This simplifies to

E =  ρ ( R1²) / 2 ∈o R

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Answer:

change in KE = -12.95 Btu

Explanation:

provided data

mass = 3000-lbm

initial velocity of vehicle vi = 10 mph = 14ft/s

final velocity of vehicle vf = 0 mph = 0 ft/s

solution

the crumple zone is designed to absorb kinetic energy upon impact

thus the change in KE is related to the initial and final speeds, expressed as:

change in KE = 0.5 × m × (vf² - vi² ).................1

Substituting in the parameters yields:

change in KE = 0.5 × 3000 × (0² - 14.7² )

change in KE = -324135 × \frac{1lbf}{32.174\ lb.ft/s^2} * \frac{1Btu}{778.17 ft.lbf}  

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5 0
28 days ago
Calculate the wavelength of a photon having 3.26 x 10^-19 joules of energy
Keith_Richards [2897]
The energy contained in a photon is determined by the formula:
E=hf
where h represents the Planck constant and f signifies the frequency of the photon. Given the energy of the photon, E=3.26 \cdot 10^{-19} J, we can rearrange the equation to deduce the photon's frequency:
f= \frac{E}{h}= \frac{3.26 \cdot 10^{-19}J}{6.6 \cdot 10^{-34}Js}=4.94 \cdot 10^{14}Hz

Now, we can use the relationship that links frequency f, wavelength \lambda, and the speed of light c to ascertain the wavelength of the photon:
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8 0
1 month ago
If you accidentally touch the "hot" wire connected to the 120 V line, how much current will pass through your body?
serg [3228]

Complete Question:

Picture yourself on an aluminum ladder on the ground, attempting to fix an electrical connection with a metal screwdriver featuring a metallic handle. Since you are sweating profusely, your body has a resistance of 1.60 kΩ.

(a) If you accidentally contact the "hot" wire from the 120 V power line, what current will flow through your body?

(b) What is the amount of electrical power transferred to your body?

Answer:

(a) 0.075A

(b) 9W

Explanation:

According to Ohm's law, the voltage (V) applied to or passing through a body corresponds to the current (I) via the relationship:

V ∝ I

=> V = I x R                 ----------------------(i)

Where;

R denotes the resistance of the body

(a) As mentioned;

Due to wet conditions, the body will conduct electricity, and possesses the following values;

V = supplied voltage = 120V

R = resistance of the wet body = 1.60kΩ = 1.6 x 1000Ω = 1600Ω

Substituting these values into equation(i):

120 = I x 1600

To find I;

I = \frac{120}{1600}

I = 0.075A

Thus the current passing through your body is 0.075A

(b) Electrical power (P), which is expressed in Watts (W), delivered to the body is the product of current (I) and voltage (V) received. Thus:

P = I x V           ---------------------(ii)

Where;

I equates to 0.075A   [as derived above]

V is 120V     [as outlined in the question]

Plugging these values into equation (ii):

P = 0.075 x 120

P = 9W

Hence, the electrical power received by your body is 9W

7 0
24 days ago
A block is suspended from a scale and then lowered into a bucket of water. The density of the water is 1 gm/cm3. The initial rea
inna [2732]
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A 2.40 kg stone is sliding in the +x-direction on a horizontal, frictionless surface. It collides with a 4.00 kg stone at rest.
inna [2732]

Answer:

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Explanation:

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P_y = m*v_y = m*v*sin(\theta)

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