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1 month ago

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If the axes of the two cylinders are parallel, but displaced from each other by a distance d, determine the resulting electric f

ield in the region R>R3, where the radial distance R is measured from the metal cylinder's axis. Assume d<(R2−R1). Express your answer in terms of the variables ρE, R1, R2, R3, d, R, and appropriate constants.

1 answer:

serg [3.5K]1 month ago

6 0

Response:

E = ρ ( R1²) / 2 ∈o R

Clarification:

Provided information

Two cylinders are aligned parallel

Distance = d

Radial distance = R

d < (R2−R1)

To determine

Express the response using the variables ρE, R1, R2, R3, d, R, and constants

Solution

We have two parallel cylinders

therefore, area equals 2 $\pi$ R × l

And we apply Gauss's Law

EA = Q(enclosed) / ∈o......1

Initially, we calculate Q(enclosed) = ρ Volume

Q(enclosed) = ρ ( $\pi$ R1² × l )

Thus, inserting all values into equation 1

produces

EA = Q(enclosed) / ∈o

E(2 $\pi$ R × l) = ρ ( $\pi$ R1² × l ) / ∈o

This simplifies to

E = ρ ( R1²) / 2 ∈o R

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Answer:

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Explanation:

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= 0.45 * 5,7876

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The volume of cells is $V_c$ = $\frac{m_c}{\rho_d}$

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The white blood cells volume is $V_w$ = 1% of the cells volume

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$= 2.315*10^{-5}m^3$

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$= 2.21*10^{-16}m^3$

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$=2.315*10^{-3} - 2.315*10^{-5}$

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$= \frac{2.29 *10^{-3}}{2.21*10^{-16}}$

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The total white blood cell count is $=\frac{V_w}{V_s}$

$= \frac{2.315 * 10^{-5}}{2.21*10^{-16}}$

$= 1.04*10^{11}$

The overall number of blood cells is $N_t= 1.037*10^{13} + 1.04*10^{11}$

$N_t=1.04*10^{13}$

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