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sweet
2 months ago
6

When the concentration of solute in a solid solution exceeds its solubility limit, a new solid solution or phase forms that has

a composition distinctly different than the original solid solution?
Chemistry
1 answer:
eduard [2.7K]2 months ago
8 0
The answer is true. A solid solution consists of a solid state solution formed by one or more solutes dissolved in a solvent, or a combination of two crystalline solids that coexist within a crystal lattice. Metal alloys, semiconductors, and moist solids are examples of such solid solutions.
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Peter performed an experiment to test which of the three compounds his teacher gave him was an ionic compound. The table shows h
lions [2927]
B is identified as an ionic compound. Explanation: This conclusion is drawn based on the characteristics of ionic compounds, which typically form crystals similar to salt (sodium chloride), are soluble in water, exhibit high boiling and melting points, possess hardness from strong intermolecular forces, and can conduct electricity—though only when dissolved or in a molten state.
5 0
1 month ago
Read 2 more answers
Arrange the steps of glycogen degradation in their proper order. Hormonal signals trigger glycogen breakdown. Glucose 6‑phosphat
VMariaS [2998]

Answer: Please see answer below

Explanation:

The sequence for glycogen degradation is as follows:[

---> Hormonal signals initiate the breakdown of glycogen.

1. Glycogen undergoes debranching through the hydrolysis of α‑1,6 linkages.

2. Blocks of three glucosyl units are relocated by remodeling α‑1,4 linkages.

3. Glucose 1‑phosphate is derived from the non-reducing ends of glycogen and is transformed into glucose 6‑phosphate.

---> Glucose 6‑phosphate enters further metabolic pathways

Glycogen degradation consists of three stages:

(1) the release of glucose 1-phosphate from glycogen,

(2) transforming the glycogen structure for continued breakdown, and

(3) converting glucose 1-phosphate into glucose 6-phosphate for subsequent metabolism.

(https://www.ncbi.nlm.nih.gov/books/NBK21190)[[TAG_34]][[TAG_35]][[TAG_36]]

4 0
1 month ago
The [H3O+] in a solution is increased to twice the original concentration. Which change could occur in the pH? 2.0 to 4.0 1.7 to
KiRa [2933]
Answer: second option: 1.70 to 1.40

Explanation:

1) pH is defined using the formula pH = - log [H₃O⁺]

2) Given that the initial concentration is x and after doubling it becomes 2x, we calculate:

pHi = - logx
pHf = - log 2x = - log 2 - logx

Thus, pHf - pHi = - log2 - logx - (- logx) = - log2 ≈ - 0.30

⇒ pHi - pHf = 0.30, indicating that the final pH (with twice the hydronium ions) is 0.30 lower than the starting pH.

3) The only option that indicates a 0.30 decline in pH is the second one: from 1.70 to 1.40. Therefore, that is the correct choice.


8 0
3 months ago
Read 2 more answers
When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq), 3.14 kJ of heat are produced. Determine the enthalpy change per mole o
Alekssandra [3086]

Answer: The change in enthalpy for each mole of zinc involved in the reaction is 152.4 kJ/mol.

Explanation:

First, we need to determine the moles of Zn and HCl.

\text{Moles of }Zn=\frac{\text{Mass of }Zn}{\text{Molar mass of }Zn}

The molar mass of Zn is 65 g/mole

\text{Moles of }Zn=\frac{1.34g}{65g/mole}=0.0206mole

and,

\text{Moles of }HCl=\text{Concentration of }HCl\times \text{Volume of solution}=0.750M\times 0.0600=0.0450mole

Next, we must identify the limiting reagent and the excess reagent.

The chemical reaction given is:

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

According to the balanced reaction we find that

1 mole of Zn reacts with 2 moles of HCl

Thus, 0.0206 moles of Zn react with 0.0206\times 2=0.0412 moles of HCl

This leads us to determine that HCl is the excess reagent because the moles provided exceed the required moles, while Zn is limiting and restricts product formation.

Now to find the enthalpy change for each mole of zinc reacting in this reaction.

From the reaction we gather that,[ [TAG_59]]

0.0206 moles of Zn yield heat = 3.14 kJ

This implies that 1 mole of Zn generates heat = \frac{3.14kJ}{0.0206mol}=152.4kJ/mol

Hence, the enthalpy change per mole of zinc involved in this reaction amounts to 152.4 kJ/mol.

5 0
2 months ago
A chemist combined chloroform (CHCl3) and acetone (C3H6O) to create a solution where the mole fraction of chloroform is 0.187. T
KiRa [2933]

Answer:

\large \boxed{\text{c = 2.50 mol/L; b = 3.96 mol/kg }}

Explanation:

1. Molar concentration

Designate chloroform as C and acetone as A.

The molar concentration for C is derived from Moles of C per Litres of solution.

(a) Moles of C

We are assuming there are 0.187 moles of C.

This resolves that step.

(b) Litres of solution

Next, identify 0.813 moles of A.

(i) Mass of each component

\text{Mass of C} = \text{0.187 mol C} \times \dfrac{\text{119.38 g C}}{\text{1 mol C}} = \text{22.32 g C}\\\\\text{Mass of A} = \text{0.813 mol A} \times \dfrac{\text{58.08 g A}}{\text{1 mol A}} = \text{47.22 g A}

(ii) Volume of each component

\text{Vol. of C} = \text{22.32 g C} \times \dfrac{\text{1 mL C}}{\text{1.48 g C}} = \text{15.08 mL C}\\\\\text{Vol. of A} = \text{47.22 g A} \times \dfrac{\text{1 mL A}}{\text{0.791 g A}} = \text{59.70 mL A}

(iii) Volume of solution

Assuming mixing doesn't alter the total volume.

V = 15.08 mL + 59.70 mL = 74.78 mL

(c) Molar concentration of C

c = \dfrac{\text{0.187 mol}}{\text{0.07478 L}} = \textbf{2.50 mol/L }\\\\\text{ The molar concentration of chloroform is $\large \boxed{\textbf{2.50 mol/L}}$}

2. Molal concentration of C

Molal concentration is calculated as moles of solute per kilograms of solvent.

Total moles of C = 0.187 mol.

Mass of A = 47.22 g = 0.047 22 kg.

\text{b} = \dfrac{\text{0.187 mol}}{\text{0.047 22 kg}} = \textbf{3.96 mol/kg }\\\\\text{The molal concentration of chloroform is $\large \boxed{\textbf{3.96 mol/kg}}$}

4 0
2 months ago
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