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Oksana_A
12 days ago
15

A sixth grade teacher takes students on a field trip to the beach. One student finds several pebbles that have a rounded shape a

nd are smooth to the touch. What process most likely shaped these pebbles?​

Chemistry
1 answer:
castortr0y [3K]12 days ago
7 0
C: The rounding of the pebbles results from weathering and deposition. Explanation: For pebbles to become smooth and rounded, they must experience the processes of weathering and deposition. Weathering involves the breakdown of rocks into smaller materials, creating new sediments, which can occur through chemical reactions or physical means. Deposition happens when eroding agents like wind or water transport sediments from one location to another, reshaping the land. Hence, the smooth shapes of the pebbles stem from the weathering of their parent rocks and subsequent deposition.
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In the molecule ClF3, chlorine makes three covalent bonds. Therefore, three of its seven valence electrons need to be unpaired.
alisha [2963]

Answer:

Explanation:

Chlorine has an electron configuration of 2, 8, 7

Within the n = 3 shell, it has 7 electrons consisting of 2 in the s subshell and 5 in the p subshell. However, one of the p electrons shifts to the d orbital, altering the electronic configuration  to be as follows

3s^23p_x^23p_y^23p_z^1  = 7

3s^23p_x^23p_y^13p_z^13d_{xy}^1

These orbitals such as sp³d hybridize, creating 7 degenerate orbitals where two orbitals are filled with electron pairs and three remain singly occupied by electrons (unpaired electrons).

3 0
13 days ago
An unknown compound, B, has the molecular formula C7H12. On catalytic hydrogenation 1 mol of B absorbs 2 mol of hydrogen and yie
castortr0y [3046]
The correct answers are B and D. Explanation: Given the information presented, we have absorption bands at 3300 cm-1 and 2200 cm-1, indicating the presence of an alkyne functional group. Furthermore, the hydrogenation of the unknown compound utilizes two moles of hydrogen, which correlates with the two pi bonds found in the alkyne group. Hence, we can eliminate choices "a" and "e." Since hydrogenation yields 2-methylhexane, option c is also dismissed, given that the methyl group attaches at carbon 3. Therefore, structures b and d remain viable.
5 0
23 days ago
A compound that is composed of carbon, hydrogen, and oxygen contains 70.6% C, 5.9% H, and 23.5% O by mass. The molecular weight
Tems11 [2777]

Answer: The molecular formula will be C_8H_8O_2

Explanation:

When percentages are provided, we assume the total mass to be 100 grams.

Thus, the mass of each element corresponds to the specified percentage.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1: convert given masses to moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{70.6g}{12g/mole}=5.9moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.9g}{1g/mole}=5.9moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.5g}{16g/mole}=1.5moles

Step 2: For determining the mole ratio, divide each molar amount by the smallest number of moles calculated.

For C = \frac{5.9}{1.5}=4

For H = \frac{5.9}{1.5}=4

For O =\frac{1.5}{1.5}=1

The resulting ratio of C: H: O= 4: 4: 1

Hence, the empirical formula obtained is C_4H_4O

The empirical weight is calculated as C_4H_4O = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now the molecular formula needs to be obtained.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{136}{68}=2

The molecular formula can be derived as=2\times C_4H_4O=C_8H_8O_2

4 0
1 month ago
Commercial grade fuming nitric acid contains about 90.0% HNO3 by mass with a density of 1.50 g/mL, calculate the molarity of the
Alekssandra [3086]
x is greater than or equal to 56Step-by-step explanation: He requires at least 56 additional cans. Hence, x should be a minimum of 56.
8 0
14 days ago
Read 2 more answers
At the boiling point, the density of the liquid is 809 g/l and that of the gas is 4.566 g/l. how many liters of liquid nitrogen
KiRa [2933]

Result: 1.68 L of liquid nitrogen is generated during the gas liquefaction process.

Clarification:

This process involves transforming gaseous nitrogen into its liquid form.

The two states possess distinct densities, thus occupying varying volumes; however, the mass remains constant.

Step 1: Calculate the mass of nitrogen gas

Let’s determine the mass of nitrogen gas associated with 297 L.

The density formula is:

Density = \frac{Mass}{Volume}

With a density of nitrogen gas at 4.566 g/L and a volume of 297 L, we can compute the mass of nitrogen gas as follows:

Using these values yields:

Mass = Density \times Volume

Mass = \frac{4.566g}{L} \times 297L

Mass = 1356g

The mass of nitrogen gas calculates to be 1356 g.

Step 2: Derive the volume of liquid nitrogen from the mass obtained

The mass for liquid nitrogen remains the same.

With the density of liquid nitrogen at 809 g/L, we can substitute this into our formula to find the volume of liquid.

Volume = \frac{Mass}{Density}

Volume = \frac{1356g}{809g/L}

Therefore, the volume of liquid nitrogen is 1.68 L.


6 0
1 month ago
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