Jessica has 12.7 moles of a compound for an experiment. How many particles of the compound does she have?

The amount of heat needed to elevate an object's temperature can be determined using the formula,
heat = mass x specific heat x (T2 - T1)
Thus, specific heat can be found with the following formula,
specific heat = heat / (mass x (T2 - T1))
By substituting,
specific heat = 645 J / ((28.4 g)(15.5 - - 11.6))
The calculated specific heat from the above equation is 0.838 J/g°C. 

 <span>(NH4)2CO3 -> 96.09 g/mol

(6.995g ammonium carbonate)(1mol ammonium carbonate/ 96.09 g ammonium carbonate) = 0.072796 mol ammonium carbonate

In this calculation, the unit 'grams' cancels out as it's present in both the numerator and the denominator, leading to 'mol' being the remaining unit.

Examining the formula (NH4)2CO3, it can be interpreted as:
2 mol (NH4) + 1 mol (CO3) = 1 mol (NH4)2CO3

This means every mole of ammonium carbonate yields one mole of carbonate ions and two moles of ammonium ions.

(0.072796 mol ammonium carbonate) = (0.072796 mol carbonate ion) + (0.363981 mol ammonium ion) </span>

Response:

$30.39

Rationale:

a lot of calculations

Please ask if you have any inquiries.

The ozonolysis of 2,4,4-trimethyl-2-pentene produces a combination of and

Explanation: In ozonolysis (where a reducing agent like Zn is involved during hydrolysis), a pi bond cleaves to generate ketones or aldehydes.

Ketones arise from the double bond's disubstituted side, whereas aldehydes come from the monosubstituted side of the same bond.

Notably, ozonolysis comprises two steps: (1) the formation of an ozonide, followed by (2) the hydrolysis of the ozonide.

Hydrolysis can transpire with or without a reducing agent. When it occurs without a reducing agent, carboxylic acid, carbon dioxide, or ketones can be produced.

In this case, 2,4,4-trimethyl-2-pentene yields a mixture of and

The reaction process is illustrated below.