Start by determining the number of moles, which is obtained by dividing 38 grams by the molar mass of 58.43 g/mol. This calculation yields 0.65 moles. The concentration is calculated by dividing the number of moles by the volume in liters. Using this formula, we can derive the total volume by dividing the number of moles by the concentration. Thus, 0.65 moles divided by 0.02M (mol/L) results in a total volume of 32.5 L.
Answer:
0.20M of nitric acid
0.00250M of KSCN
Explanation:
In the case of nitric acid, the solution's dilution changes from 10.00mL to 100.00mL, resulting in a 1/10 dilution. Given the original concentration of nitric acid is 2.0M, the updated concentration becomes: 2.0M×(1/10)=0.20M of nitric acid
Similarly, the dilution of KSCN extends from 50.00mL to 100.00mL, equal to a 1/2 dilution. Consequently, the new concentration of KSCN turns out to be:
0.00500M × (1/2) = 0.00250M of KSCN
I hope it aids you!
Water transitions to ice when temperatures drop too low, while it turns into gas when temperatures rise too high.
Conversely, ice transforms back into water when heated, remaining unchanged if temperatures are too low.
Furthermore, gas transitions to water when cooled and can freeze into ice if cooled further, continuing this cycle.
I hope this clarifies things.
The quantity is 6.074 X 10¹⁸ molecules. To calculate the molecular weight (MM) of the compound C₂₇H₄₆O, we use the formula: 27*(MM of C) + 46*(MM of H) + (MM of O). This leads to: 27*(12.0107) + 46* (1.00784) + (15.999) = 324.2889 + 46.36064 + 15.999 = 386.64854 g. The molar mass of any compound indicates the number of molecules found in one mole, which is 6.022 X 10²³ (Avogadro's number). So, if 386.64854 g of C₂₇H₄₆O consists of 6.022 X 10²³ cholesterol molecules, we can determine how many molecules are found in a deposit of 3.9mg or 0.0039g of C₂₇H₄₆O by using the unitary method. Number of molecules = 6.074 X 10¹⁸ molecules.
