At a location where the acceleration due to gravity is 9.807 m/s2, the atmospheric pressure is 9.891 × 104 Pa. A barometer at th

Answer:

The result is 0.750 NC

Explanation:

I am also taking the same test

This problem can be solved using Ampere’s Law:

<span>Bh = μoNI </span>

In this equation:

B = Magnetic Field

h = length of the coil

<span>μo = permeability = 4π*10^-7 T·m/A</span>

N = number of coil turns

I = current

Given values are B = 0.0015T, I = 1.0A, h = 10 cm = 0.1m<span>

Utilizing Ampere's law to determine the number of turns:
This can be rearranged to:
<span>N = Bh/μoI</span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0)
N = 119.4

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<span>Final answer: 119.4 turns</span>

Answer:

0.0984

Explanation:

The first diagram below illustrates a free body diagram that will aid in resolving this problem.

According to the diagram, the force's horizontal component can be expressed as:

Substituting 42° for θ and 87.0° for

Meanwhile, the vertical component is:

Again substituting 42° for θ and 87.0° for

In resolving the vector, let A denote the components in mutually perpendicular directions.

The magnitudes of both components are illustrated in the second diagram provided and can be represented as A cos θ and A sin θ

The frictional force can be expressed as:

Where;

is the coefficient of friction

N = the normal force

Also, the normal reaction (N) is calculated as mg - F sin θ

Substituting . Normal reaction becomes:

By balancing the forces, the horizontal component of the force equals the frictional force.

The horizontal component is described as follows:

Rearranging the equation above to isolate leads to:

Substituting in the following values:

m = 73 kg

g = 9.8 m/s²

Thus:

Therefore, the coefficient of friction is = 0.0984

Answer:

Jari

Explanation:

To determine who is traveling faster, we need to evaluate their gradients. A steeper slope indicates a higher speed.

For Jari's path, starting point is (0, 0) and (6, 7) is another point.

The gradient is the difference in y divided by the difference in x:

Change in y=7-0=7

Change in x=6-0=6

Thus, the slope equals 7/6.

For Jade, her first point is (0, 10) and another is (6, 16).

Change in y=16-10=6

Change in x=6-0=6

Thus, the slope equals 6/6=1.

It's evident that 7/6 exceeds 6/6 or 1, proving Jari is quicker than Jade.

Answer:

Explanation:

a) La fuerza neta que actúa sobre la caja en la dirección vertical es:

Fnet=Fg−f−Fp *sin45 °

aquí Fg representa la fuerza gravitacional, f es la fuerza de fricción, y Fp es la fuerza de empuje.

Fnet=ma

ma=Fg−f−Fp *sin45 °

​a=

=0.24 m/s²

Vf =Vi +at

=0.48+0.24*2

Vf=2.98 m/s

b)

Fnet=Fg−f−Fp *sin45 °

=Fg−0.516Fp−Fp *sin45 °

=30-1.273Fp

Fnet=0 (Ya que la velocidad es constante)

Fp=30/1.273

=23.56 N