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Radda
4 days ago
12

How many top quark lifetimes have there been in the history of the universe (i.e., what is the age of the universe divided by th

e lifetime of a top quark)? Note that these powers of 10 follow the same rules that any exponents would follow.
(The age of the universe is around 100,000,000,000,000,000s. A top quark has a lifetime of roughly 0.000000000000000000000001s. Writing numbers out with all these zeros is not very convenient. Such quantities are usually written as powers of 10. The age of the universe can be written as 1017s and the lifetime of a top quark as 10−24s.
Note that1017 means the number you would get by multiplying 10 times 10 times 10... a total of 17 times. This number, as you can see above, would be a one followed by seventeen zeros. Similarly, 10−24 is the result of multiplying 0.1 (or 1/10) times itself 24 times. As seen above, this is written as 23 zeros after the decimal point followed by a one.)
Physics
1 answer:
inna [2.2K]4 days ago
6 0

Answer:

times1.0\cdot 10^{41}

Explanation:

To approach this question, we first express the universe's age and the top quark's lifespan in scientific notation.

Age of the universe:

T=100,000,000,000,000,000s = 1.0\cdot 10^{17} s (1 followed by 17 zeros)

Lifetime of the top quark:

\tau = 0.000000000000000000000001s = 1.0\cdot 10^{-24} s (the decimal point is shifted 24 places to the right)

To provide an answer, we will compute the ratio of the age of the universe to the lifespan of the top quark:

r = \frac{T}{\tau}=\frac{1.0\cdot 10^{17} s}{1.0\cdot 10^{-24} s}=1.0\cdot 10^{41}

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A 0.2-kg steel ball is dropped straight down onto a hard, horizontal floor and bounces straight up. The ball's speed just before
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Answer:

Explanation:

Provided:

mass of the steel ball m=0.2\ kg

initial velocity of the ball u=10\ m/s

Final velocity of the ball v=-10\ m/s (moving upwards)

The impulse given is determined by the change in the momentum of the object.

<ptherefore the="" impulse="" j="" is="" defined="" by="">

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16 days ago
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Calculate the minimum average power output necessary for a person to run up a 12.0 m long hillside, which is inclined at 25.0° a
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Answer:

Power output, P = 924.15 watts

Explanation:

We have the following parameters:

Length of the ramp, l = 12 m

Weight of the individual, m = 55.8 kg

Incline angle with respect to the horizontal, \theta=25^{\circ}

Elapsed time, t = 3 s

Let h represent the vertical height of the hill:

h=l\ sin\theta

h=12\times \ sin(25)

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Power P required for a person to ascend the hill can be expressed as:

P=\dfrac{E}{t}

P=\dfrac{mgh}{t}

P=\dfrac{55.8\times 9.8\times 5.07}{3}

P = 924.15 watts

This indicates that a minimum average power output of 924.15 watts is essential for an individual to ascend this elevation. Thus, this is the answer sought.

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17 days ago
The amount of electric energy consumed by a 60.0-watt lightbulb for 1.00 minute could lift a
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Answer:

Explanation:

For a 60W light bulb used for 1 minute:

P = 60 W

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This energy is capable of lifting an object weighing 10N.

W = 10N

This indicates conversion of electrical energy into potential energy.

Let's calculate the electrical energy:

Power describes the rate of work done.

Power = Work / time

Thus, work = power × time

Work = 60 × 60

Work = 3600 J

Potential energy calculation:

P.E = mgh

Where the weight is given by:

W = mg

Therefore, P.E = W·h

P.E = 10·h

Thus, we equate:

Potential energy = Electrical energy

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6 0
27 days ago
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Answer:

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When an object remains at rest, it is indicative that no net force acts upon it.

The downward gravitational force from Earth must be counterbalanced by an upward force of equal magnitude in order to maintain rest.

This upward force is provided by the normal force, which adjusts to satisfy Newton’s 2nd Law and is always perpendicular to the surface supporting the object (in this instance, the ground).

At the molecular level, this normal force comes from the ground's bonded molecules acting like tiny springs, compressed by the object’s molecules, providing an upward restorative force.

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23 days ago
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