Which pair of graphs represent the same motion of an object
2 answers:
Answer:
C
Explanation:
This graph pair represents displacement versus time, where the displacement-time graph is concave upward and can be modeled by a parabolic function. The velocity at any moment is the slope of the displacement-time graph.
where:
s = displacement
t = time
Because the derivative of a parabolic function is linear, the velocity-time graph shows a straight inclined line. At time t=0, the slope of the displacement graph is zero, corresponding to zero velocity on the velocity graph.
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Response:
For a transition metal complex in solution exhibiting an absorption peak at 450 nm, which falls within the blue section of the visible spectrum, the corresponding (complementary) color of this solution is orange (option B).
Rationale:
The amount of UV-visible light absorbed indicates that some electromagnetic radiation successfully passes through the sample and is perceivable by the human eye. Thus, the color apparent in the visible spectrum of a complex aligns with the wavelengths of light it allows to pass rather than those it absorbs. The color that is absorbed will be complementary to the one that is transmitted.
In the accompanying image, you can view the associated wavelengths alongside their respective colors. By identifying the wavelength associated with the absorbed color, you will be able to see the complementary color that is visible or reflected.
For a transition metal complex in solution exhibiting an absorption peak at 450 nm, which falls within the blue section of the visible spectrum, the corresponding (complementary) color of this solution is orange (option B).
Answer with Explanation:
Concepts and reasoning
The principle for addressing this question is that a capacitor in an RC circuit allows current to flow until fully charged. Once charged, it prevents any further current from moving through. Conversely, the situation is different with an inductor in an RL circuit. In accordance with Faraday's law, an inductor generates an electromagnetic force to counteract the applied voltage, but when no change in flux occurs, it behaves akin to a regular wire as if the inductor is absent.
In the accompanying diagram, a resistor is connected in series with a capacitor.
As we observe
the voltage across both the capacitor and the source.Voltage across a resistor in an RC circuit.
Voltage across a resistor in an RL circuit.
Answer:
The distance before stopping is 1.52 m,
velocity is 4.0 m/s on the y-axis
Explanation:
The particle’s motion is two-dimensional due to acceleration along both the x and y axes; each axis can be addressed independently for calculations.
a) At the moment the particle starts to reverse, its velocity should be zero (Vfx = 0)
Vfₓ = V₀ₓ + aₓ t
t = - V₀ₓ/aₓ
t = - 2.4/(-1.9)
t= 1.26 s
When the particle stops, we calculate its position
X1 = V₀ₓ t + ½ aₓ t²
X1= 2.4 1.26 + ½ (-1.9) 1.26²
X1= 1.52 m
At this point, the particle begins returning.
b) The velocity comprises both x and y components.
For the x section, Vₓ = 0 m/s indicates a halt, but the y component retains a velocity
Vfy= Voy + ay t
Vfy= 0 + 3.2 1.26
Vfy = 4.0 m/s
Thus, the velocity reads as
V = (0 x^ + 4.0 y^) m/s
c) To graph the motion, we create a table listing position x and y at given time intervals; let's begin the calculations for equations
X = V₀ₓ t+ ½ aₓ t²
Y = Voy t + ½ ay t²
X= 2.4 t + ½ (-1.9) t²
Y= 0 + ½ 3.2 t²
X= 2.4 t – 0.95 t²
Y= 1.6 t²
With these equations, we construct two graphs for position against time, one for the x-axis and another for the y-axis
Chart for graphing
Time (s) x(m) y(m)
0 0 0
0.5 0.960 0.4
1 1.45 1.6
1.50 1.46 3.6
2.00 1.00 6.4
