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marissa
20 days ago
12

A crate on a motorized cart starts from rest and moves with a constant eastward acceleration ofa= 2.60 m/s^2. A worker assists t

he cart by pushing on the crate with a force that is eastward andhas magnitude that depends on time. According to F(t) = (5.40 N/s)t. What is the instantaneouspower supplied by this force at t= 4.70 s
Physics
1 answer:
Keith_Richards [3.2K]20 days ago
8 0

Response:

To find power, we must first determine the work done by the force.

1) We will use the following equation to calculate work:

\int\limits {F} \, dx

The force is provided by the problem; our goal is to express 'dx' in terms of 't'

2) It's known that:

\frac{dV}{dt} = a = 2.6

Thus, we have:

v = 2.6t

Then:

\frac{dx}{dt} = V = 2.6t\\ \\dx = 2.6t*dt

3) Finally, substituting all known values gives us:

\int\limits^{4.7}_{0} {5.4t*2.6t} \, dt

After some calculations, the resulting work is:

161.9638 J.

4) To find power, we will use the following equation:

P = \frac{W}{t}

Thus

P = 161.9638/4.7 = 34.46 W

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According to Newton's second law, provided F is directed horizontally,

• the net horizontal force acting on the larger block is

F - µmg = 3mA

where µmg represents the friction experienced by the larger block from contact with the smaller block, µ is the static friction coefficient between both blocks, and A indicates the acceleration of the block;

• the net vertical force on the larger block is

4mg - 3mg - mg = 0

where 4mg denotes the magnitude of the normal force exerted by the surface on the combined mass of both blocks, 3mg corresponds to the weight of the larger block, and mg indicates the weight of the smaller block;

• the net horizontal force acting on the smaller block is

µmg = ma

where µmg again signifies the friction between both blocks; however, it is important to note that this force aligns in the same direction as F. It is the sole force influencing the smaller block in the horizontal direction, thus (b) static friction causes the smaller block's acceleration;

• the net vertical force on the smaller block is

mg - mg = 0

where mg represents the force of both the normal force from the larger block pushing up against the smaller one, and the weight of the smaller block.

(You should be able to create your own free-body diagrams based on the forces discussed.)

(c) Solve the equations stated above to find A and a:

A = (F - µmg) / (3m)

a = µg

5 0
12 days ago
9. A 2 liter bottle of Coke weighs about 2 kilograms. If that bottle were combined with an equal amount of anti-Coke, how many J
Maru [3345]

Answer:

The energy expected to be released is calculated to be 4182 Joules.

Explanation:

The total mass of coke is 2 kg, which is equivalent to 2000 g

1 calorie per gram corresponds to 4.184 Joules of energy

4.184 J/gC * 2000g results in 8368 J

1 food calorie approximates to 4186 J

By subtracting, we find 8368 - 4186

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1 month ago
1. A 930-kg car traveling 56 km/h comes to a complete stop in 2.0 s. What is the
kicyunya [3294]
The force exerted on the car during the stop measures 6975 N. Explanation: Given that the mass (m) is 930 kg, speed (s) at 56 km/h converts to 15 m/s, and the stopping time (t) is 2 s, we compute the force using F = m * a. Here, acceleration (a) can be obtained through a = s/t. The total force calculation confirms that F = 930 kg * (15 m/s) / 2 s results in 6975 N.
6 0
20 days ago
A beam of electrons moves at right angles to a magnetic field of 4.5 × 10-2 tesla. If the electrons have a velocity of 6.5 × 106
Softa [3030]
Greetings!

Using the formula F = Bqv sin theta, we define F as Force, B as magnetic flux density, q as charge, v as velocity, and theta as the angle created by the moving electrons in relation to the magnetic field.

^^^You can compute the force using that equation^^^

In conclusion, your result would MOST LIKELY be "B".

"<span>-3.9 × 10-14 N"
</span>
<span>I trust my response has been beneficial. Thank you for your question. We look forward to assisting with more inquiries. Have a wonderful day ahead!:</span>
6 0
17 days ago
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Sav [3153]

Answer:

I'm uncertain

Explanation:

since I didn't provide a correct answer, continue with my inquiries and you can use 'I'm uncertain' for 100 points.

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