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Arada
1 month ago
12

A windowpane is half a centimeter thick and has an area of 1.0 m2. The temperature difference between the inside and outside sur

faces of the pane is 15° C.
What is the rate of heat flow through this window? (Thermal conductivity for glass is 0.84 J/s⋅m⋅°C.)
a. 50 000 J/sb. 2 500 J/sc. 1 300 J/sd. 630 J/s
Physics
1 answer:
Keith_Richards [3.2K]1 month ago
3 0

To tackle this problem, one must utilize the ideas related to the rate of heat flux defined in energetic terms. The heat transfer rate signifies the quantity of heat moved per time unit through a specific material. This can be calculated mathematically in the following manner:

\frac{Q}{t} = \frac{kA}{L} (T_H - T_C)

Where

k = 0.84 J/s⋅m⋅°C (This is the thermal conductivity of the substance)

A = 1m^2 Area

L = 5*10^{-3}m Length

T_H= Temperature of the "hot" reservoir

T_C= Temperature of the "cold" reservoir

Substituting our specific values provides us with,

\frac{Q}{t} = \frac{kA}{L} (T_H - T_C)

\frac{Q}{t} = \frac{(0.84)(1)}{0.005} (15)

\frac{Q}{t} = 2520J/s

Thus, the accurate option is B.

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5 0
1 month ago
A Federation starship (8.5 ✕ 106 kg) uses its tractor beam to pull a shuttlecraft (1.0 ✕ 104 kg) aboard from a distance of 14 km
Keith_Richards [3271]
Consider the diagram below.

m₁ = 8.5 x 10⁶ kg, the starship's mass
m₂ = 10⁴ kg, the shuttlecraft's mass
a₁ =  acceleration of the starship
a₂ = the acceleration of the shuttle
F = 4 x 10⁴ N, the force exerted

Let y represent the distance covered by the starship
Let x denote the distance covered by the shuttlecraft
If t indicates the travel time, then
y = 0.5a₁t²                  (1)
x = 0.5a₂t²                  (2)

F = m₁a₁ = m₂a₂         (3)
Additionally,
x + y = 14000 m          (4)

From (2), we derive
a₁ = (4 x 10⁴ N)/(8.5 x 10⁶ kg) = 4.706 x 10⁻³ m/s²
a₂ = (4 x 10⁴ N)/(10⁴ kg) = 4 m/s²

From (1), (2) and (4), we find
0.5*(t s)²*(4 + 4.706 x 10⁻³ m/s²) = 14000 m
2.002353t² = 14000
t² = 6991.774 s²
t = 83.617 s

Thus
x = 0.5*4*6991.774 = 13984 m = 13.984 km
y = 0.5*4.706 x 10⁻³*6991.774 = 16.452 m

The starship moves roughly 16.5 meters while towing the shuttlecraft by 13.98 kilometers.

Result: The starship shifts by 16.5 m (to the nearest tenth)

3 0
2 months ago
In the past, salmon would swim more than 1130 km (700 mi) to spawn at the headwaters of the Salmon River in central Idaho. The t
Keith_Richards [3271]

Answer:

E_t_o_t_a_l=7.603MJ

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\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ

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2 months ago
A ball with a mass of 0.5 kilograms is lifted to a height of 2.0 meters and dropped. It bounces back to a height of 1.8 meters.
kicyunya [3294]
Hello! Thanks for sharing your query here.

To determine the change in potential energy, you would utilize the formula:

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delta PE = 0.5*9.81*(2-1.8)
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The kinetic energy is derived from the potential energy.
3 0
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