A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diame

Initially, we need to calculate the acceleration required for the car to halt from its initial speed based on the distance traveled. This can be done using the formula,
                                             2ad = Vf² - Vi²
where a represents acceleration, d is distance, and Vf and Vi are the final and initial speeds respectively. Plugging in the known quantities,
           2(a)(35 m) = (0 m/s)² - ((65 km/h) x (1000 m/ 1 km) x (1 hr / 3600 s))²
The resulting acceleration is −4.66 m/s².
To calculate the force required to stop the car, we multiply the mass by the acceleration. This calculation yields -4,660 N, and we take the absolute value, which is 4,660 N. 

Answer:

The plane's speed in relation to the ground is 300.79 km/h.

Explanation:

Provided details include:

Wind speed = 75.0 km/hr

Plane's airspeed = 310 km/hr

Next, we must find the ground speed of the plane

Calculating the angle

Using the angle formula

Where v' represents the wind speed

v represents the plane's speed

We will substitute the values into the formula

Now, we must find the resultant speed

Using the resultant speed formula

Insert the values into the formula

Consequently, the plane's speed in relation to the ground equals 300.79 km/h.

Refer to the diagram shown below.

m₁ = 1100 kg represents the mass of the car.
m₂ = 700 kg indicates the combined mass of the trailer and boat.
F = 1900 N is the driving force acting on the vehicle.
N₁ denotes m₁g, the normal force on the car.
N₂ corresponds to m₂g, the normal force on the trailer and boat.
Frictional forces are represented by μN₁ and μN₂, where μ is the coefficient of kinetic friction.
T signifies the force in the connection between the car and the trailer.

Part (a)
Let R₁ signify the total resistance acting against the motion of the car, boat, and trailer.
With the acceleration at 0.550 m/s², it follows that
(m₁ + m₂ kg)*(0.55 m/s²) = F
(1100 + 700 kg)*(0.55 m/s²) = (1900 - R₁) N.
This leads to the equation 990 = 1900 - R.
Therefore, R₁ = 910 N.

Answer: The total resistive force amounted to 910 N.

Part (b)
The trailer and boat experience 80% of the resisting forces.
Let R₂ denote this resistive force.
Thus,
R₂ = 0.8*R₁ = 728 N.
Assuming T is the tension in the hitch connecting the car and trailer, it follows:
T - R₂ = m₂(0.55 m/s²)
(T - 728 N) = (700 kg)*(0.55 m/s²).
This leads to T - 728 = 385.
Thus, T equals 1113 N.

Answer: The tension in the hitch is 1113 N.

Answer:

The amount of heat that enters the gas throughout this two-step process totals 120 cal.

Explanation:

Given that,

Moles present = 3

Heat capacity at volume held constant = 4.9 cal/mol.K

Heat capacity at pressure held constant = 6.9 cal/mol.K

Starting temperature = 300 K

Ending temperature = 320 K

We are tasked with determining the heat absorbed by the gas at constant pressure

Employing the heat formula

Substituting the values into the equation

Next, we calculate the heat absorbed by the gas at constant volume

Using the corresponding heat formula

Insert the values into the formula

Now, it's necessary to evaluate the total heat flow into the gas during both steps

Using the total heat formula

Thus, the heat that transfers into the gas throughout this two-step process amounts to 120 cal.

Answer:

The correct response is:

1. KE Increases, PE Increases, ME Increases.

Explanation:

In this context, kinetic energy refers to the energy associated with an object's motion. Kinetic energy can be defined as the energy required to accelerate a mass from rest to a specified velocity, which it maintains once that speed is reached:

KE = 1/2 mv².

This definition indicates that KE is on the rise.

Potential energy is the energy stored in a body due to its position in a gravitational field:

PE = mgh,

which increases as the object is elevated against gravitational pull.

Since both kinetic and potential energies are increasing, it follows that the total mechanical energy (ME) is also rising:

ME = PE + KE.