Normally, jet engines push air out the back of the engine, resulting in forward thrust, but commercial aircraft often have thrus

Answer:

The period of a wave is the duration it takes to complete one full oscillation, such as from one peak to the next trough.

Since the period is expressed in microseconds, it needs to be converted into seconds.

The conversion is:

Accordingly, the wave's period in seconds is .

a) Average velocity: 2.8 m/s

b) Average velocity: 5.2 m/s

c) Average velocity: 7.6 m/s

Explanation:

a)

The car's position over time t can be described by

where

To find the average velocity, we divide the displacement by the elapsed time:

At time t = 0, the position is:

At time t = 2.00 s, the position is:

This leads us to the displacement of

The duration for this interval is

Therefore, the average velocity during this period is

b)

At time t = 0, the position is:

At time t = 4.00 s, the position is:

Thus, the displacement is

The time interval is

This yields an average velocity of

c)

The position at t = 2 s is:

And at t = 4 s it is:

This gives us a displacement of

While the time interval is

So the resulting average velocity is

Find out more about average velocity:

Answer:

The amount of heat that enters the gas throughout this two-step process totals 120 cal.

Explanation:

Given that,

Moles present = 3

Heat capacity at volume held constant = 4.9 cal/mol.K

Heat capacity at pressure held constant = 6.9 cal/mol.K

Starting temperature = 300 K

Ending temperature = 320 K

We are tasked with determining the heat absorbed by the gas at constant pressure

Employing the heat formula

Substituting the values into the equation

Next, we calculate the heat absorbed by the gas at constant volume

Using the corresponding heat formula

Insert the values into the formula

Now, it's necessary to evaluate the total heat flow into the gas during both steps

Using the total heat formula

Thus, the heat that transfers into the gas throughout this two-step process amounts to 120 cal.

Answer:

R=V/I=6/2=3 ohm

time = 5 minutes = 5*60=300 seconds

I=2 A

Energy = I²Rt=(2)²*3*300=4*900=3600 J

Answer:

Induced EMF is 2 x 10⁻³ volts

Explanation:

B = strength of the magnetic field aligning with the loop's axis = 1 T

= area change rate of the loop = 20 cm²/s = 20 x 10⁻⁴ m²

θ = the angle formed by the magnetic field and area vector = 0

E = the induced EMF across the loop

EMF can be calculated using the formula

E = B

E = (1) (20 x 10⁻⁴ )

E = 2 x 10⁻³ volts

E = 2 mV