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Nookie1986
3 months ago
9

A man runs at 7.5 m s-1 due east across the deck of a ship which moves at 10.0 m s-1 due north. Determine the resultant velocity

of the man( his velocity relative to the water)
Physics
1 answer:
Keith_Richards [3.2K]3 months ago
7 0
The resultant velocity is 12.5 m/s North/east. I visualized it as a graph, determining the distance between the coordinates (0,0) and (10, 7.5).
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A point charge with charge q1 is held stationary at the origin. A second point charge with charge q2 moves from the point (x1, 0
kicyunya [3294]

Answer:

W=kq_1q_2(\dfrac{1}{x_1}-\dfrac{1}{\sqrt{x_2^2+y_2^2}})

Explanation:

The position of the charge q₁ is established at (0,0)

Meanwhile, the charge q₂ is located at (x₁,0)

Thus, the electric potential energy between these two charges is determined by:

U_1=k\dfrac{q_1q_2}{x_1}

Now, the location of charge q₂ shifts from (x₁,0) to (x₂,y₂). The updated electric potential energy between the charges can be represented as:

U_2=k\dfrac{q_1q_2}{\sqrt{x_2^2+y_2^2}}

According to the work-energy theorem, the alteration in potential energy corresponds to the work performed. This is expressed mathematically as:

W=-\Delta U

W=-(U_2-U_1)

W=(U_1-U_2)

W=(k\dfrac{q_1q_2}{x_1}-k\dfrac{q_1q_2}{\sqrt{x_2^2+y_2^2}})

W=kq_1q_2(\dfrac{1}{x_1}-\dfrac{1}{\sqrt{x_2^2+y_2^2}})

Consequently, the work done by the electrostatic force on the moving charge is kq_1q_2(\dfrac{1}{x_1}-\dfrac{1}{\sqrt{x_2^2+y_2^2}}). Therefore, this concludes the solution.

3 0
3 months ago
A group of science and engineering students embarks on a quest to make an electrostatic projectile launcher. For their first tri
Maru [3345]
The charge on the plastic cube is determined as follows.
7 0
3 months ago
A 45.0-kg person steps on a scale in an elevator. The scale reads 460 n. What is the magnitude of the acceleration of the elevat
ValentinkaMS [3465]
The elevator's acceleration is 0.422 m/s². To clarify the solution: By applying Newton's Law, the net forces in the motion's direction equal the mass multiplied by the acceleration. The forces comprise 460 N in the motion's direction and the person's weight acting in the opposite direction... The weight is determined by the mass and gravity's acceleration (W = mg). Here m = 45 kg and g = 9.8 m/s², leading to W = 441 N. With the scale indicating 460 N, we apply F - W = ma, yielding 19 = 45 a. Dividing both sides by 45 gives a = 0.422 m/s².
4 0
2 months ago
A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i
Sav [3153]
The force that the car applies on the truck will be 6000 N in the reverse direction.

As per the information provided, the car's mass is one-fourth that of the truck

The truck exerts a force of 6000 N onto the car

We aim to determine the force that the car exerts on the truck

According to Newton's third law, every action has an equal and opposite reaction

Hence, the force from the car on the truck is 6000 N in the opposite direction

7 0
2 months ago
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