Answer:
a) 
b) 
c) 
Explanation:
According to the problem, the distance from the building where the ball hits is 16m, and its final elevation exceeds the initial height by 8m.
With this information, we can compute the ball’s starting speed.
a) Let's first assess the horizontal trajectory.
(1)
This gives us our initial equation.
Next, we need to examine the vertical trajectory.
Utilizing 
in our first equation (1)
Now let’s solve for t.
The ball takes two seconds to reach the adjacent building, allowing us to compute its initial speed.
b) To determine the velocity magnitude just before impact, we must calculate both x and y components.
The computed velocity magnitude is:
c) The ball's angle is:
Answer: SG = 2.67
The specific gravity for the sand is 2.67
Explanation:
Specific gravity is determined by the formula: density of the substance/density of water
Provided information;
Mass of sand m = 100g
The volume of sand equals the volume of water it displaces
Vs = 537.5cm^3 - 500 cm^3
Vs = 37.5cm^3
Calculating density of sand = m/Vs = 100g/37.5 cm^3
Ds = 2.67g/cm^3
Density of water Dw = 1.00 g/cm^3
Thus, the specific gravity of the sand can be expressed as
SG = Ds/Dw
SG = (2.67g/cm^3)/(1.00g/cm^3)
SG = 2.67
The specific gravity of the sand stands at 2.67
Answer:
A) The updated amplitude = 0.048 m
B) Period T = 0.6 seconds
Explanation: Please refer to the attached documents for the solution.
The response is 176 minutes. The translation of 456 g equals 0.456 kg. The specific heat of ice is 2093 J kg⁻¹, used to calculate heat required for a 25-degree rise, determined by mass multiplied by specific heat and temperature increase. The necessary calculations yield a total heat load of 176164 J. Finally, by dividing heat required by heat supply rate, we ascertain that it will take approximately 176.16 minutes.
Torque = Force * Distance perpendicular
Torque = 15 N * 2 m = 30 Nm
