Answer:
Temperature T = 394.38 K
Explanation:
The full solution and detailed explanation regarding the above question and its specified conditions can be found below in the accompanying document. I trust my explanation will assist you in grasping this particular topic.
Answer:
you may be struggling to pinpoint the separation between your inquiry and my perspective
Answer:


Explanation:
A liquid food containing 12% total solids is heated via steam injection at a pressure of 232.1 kPa (see Fig. E3.3). The product starts at a temperature of 50°C and has a flow rate of 100 kg/min, being elevated to a temperature of 120°C. The specific heat of the product varies with its composition as follows:
and the
specific heat of the product at 12% total solids is 3.936 kJ/(kg°C). The goal is to calculate the quantity and minimum quality of steam required to ensure that the leaving product has 10% total solids.
Given
Product total solids in (
) = 0.12
Product mass flow rate (
) = 100 kg/min
Product total solids out (
) = 0.1
Product temperature in (
) = 50°C
Product temperature out (
) = 120°C
Steam pressure = 232.1 kPa at (
) = 125°C
Product specific heat in (
) = 3.936 kJ/(kg°C)
The mass equation is:


Also 
Therefore: 
The energy balance equation is:


kJ/(kg°C)
By substituting values into the energy equation:



From the properties of saturated steam at 232.1 kPa,
= 524.99 kJ/kg
= 2713.5 kJ/kg
% quality = 
Any steam quality above 63.5% will result in higher total solids in the heated product.
Answer:
The calculated result is 11.7 ft
Explanation:
You can apply the combined gas law, which incorporates Boyle's law, Charles's law, and Gay-Lussac's Law, because hydrogen demonstrates ideal gas behavior under these specific conditions.

where the subscripts indicate "p" for pressure, "V" for volume, and "T" for temperature (in Kelvin) at varying moments. Let's denote
as the balloon at 150,000 ft so


and
.
Then
represents the point at which the balloon is on the ground.
and
.
Based on the first equation
, we find
and consequently the radius turns out to be
.