Explanation:
At a temperature of
and relative humidity of 86%, the humidity ratio stands at 0.0223 with a specific volume of 14.289.
At a temperature of
and relative humidity of 40%, the humidity ratio is 0.0066 while the specific volume is 13.535.
To determine the mass of air, the following formula can be used:

Now, we will calculate the volume

The duration required to fill the cistern can be determined with the equation:

By substituting the values into the preceding formula, we find:

Thus, the hours necessary to fill the cistern amount to 4.65 hours.
Answer:
The following represents the answer.
Explanation:
Calculation for the maximum yield strength of a single crystal of Fe subjected to tension can be found in the attached image.
The maximum yield strength value is 54 MPa.
Response:
a) 144.000 seconds
b) and c) Battery voltage and power graphs are in the attached image.
where D:{0<t h="" />
d) 1620 J
Description:
a) The initial response is derived via a rule of three

b) Using the line equation from the starting point (0 seconds, 1.5 V)
where m denotes the slope.

where V represents voltage in volts and t signifies time in seconds
along with P and m.
![V=-\frac{0.5}{144000} t + 1.5 V[tex] c) Using the equation VPOWER IS DEFINED AS:[tex] P(t) = v(t) * i(t) [tex]so.[tex] P(t) = 9mA * (-\frac{0.5}{144000} t + 1.5) [tex][tex]P(t) = - (31.25X10^{-9}) t + 0.0135](https://tex.z-dn.net/?f=V%3D-%5Cfrac%7B0.5%7D%7B144000%7D%20t%20%2B%201.5%20V%5Btex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%20%3C%2Fp%3E%3Cp%3E%3Cstrong%3Ec%29%20Using%20the%20equation%20V%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EPOWER%20IS%20DEFINED%20AS%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%20P%28t%29%20%3D%20v%28t%29%20%2A%20i%28t%29%20%5Btex%5D%3C%2Fp%3E%3Cp%3Eso.%3C%2Fp%3E%3Cp%3E%5Btex%5D%20P%28t%29%20%3D%209mA%20%2A%20%28-%5Cfrac%7B0.5%7D%7B144000%7D%20t%20%2B%201.5%29%20%5Btex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3E%5Btex%5DP%28t%29%20%3D%20-%20%2831.25X10%5E%7B-9%7D%29%20t%20%2B%200.0135)
d) By evaluating that count.


Answer:
M_o = 18.84 N*m clockwise.
Explanation:
Given:
- Force F = 120 N
- Length b = 610 mm
- Height h = 330 mm
Required:
Calculate the moment M_o at the origin and its direction:
Solution:
- The force is divided into components F_x and F_y along the base b and height h, respectively:
F_x = F*cos(Q)
F_x = F*(h / sqrt(h² + b²))
F_x = 120*(330 / sqrt(330² + 610²))
F_x = 57.098 N
- The F_y component can be excluded as it passes through the origin, resulting in zero moment.
- The moment at point O is calculated as:
M_o = F_x * h
M_o = 57.098*.33
M_o = 18.84 N*m clockwise.