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Dmitry_Shevchenko
2 months ago
11

Discuss how personal choice can enhance your safety when exercising.

Physics
2 answers:
inna [3.1K]2 months ago
8 0
In summary, you can make choices regarding the timing, location, and nature of your exercise, and these decisions can significantly impact your safety during physical activity. To minimize injury risk, start slowly with low-intensity exercises, use suitable footwear, warm up before working out, and cool down afterward. Awareness of your environment is crucial while exercising outdoors.
Maru [3.3K]2 months ago
5 0

<span>In essence, your decisions regarding the timing, location, and manner of your exercise can either enhance or jeopardize your safety while engaging in physical activities.</span>

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Answer:

The energy expected to be released is calculated to be 4182 Joules.

Explanation:

The total mass of coke is 2 kg, which is equivalent to 2000 g

1 calorie per gram corresponds to 4.184 Joules of energy

4.184 J/gC * 2000g results in 8368 J

1 food calorie approximates to 4186 J

By subtracting, we find 8368 - 4186

Hence, the total energy that will be released amounts to 4182 Joules.

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2 months ago
Which characteristics of Earth’s orbit are in agreement with Kepler’s second law? Check all that apply.
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6 0
2 months ago
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An object is attached to a hanging unstretched ideal and massless spring and slowly lowered to its equilibrium position, a dista
Sav [3153]

Answer:

        h = 12.8 cm

Explanation:

The initial parameters are as follows:

distance = 6.4 cm

  • when the object descends, its weight matches the spring's force

        weight = spring force

         mg = ky... equation 1

  • potential energy stored in a stretched spring = work done by the spring

        mgh = 0.5 x k x h^{2}....equation 2

  • Substituting from equation 1 into equation 2

                kyh =  0.5 x k x h^{2}

                y =  0.5 x h

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  • where y is 6.4, yielding the maximum elongation as

          h = 2 x 6.4 = 12.8 cm

6 0
3 months ago
A ski lift is used to transport people from the base of a hill to the top. If the lift leaves the base at a velocity of 15.5 m/s
Yuliya22 [3333]
This can be determined using the principle of energy conservation. The ski lift begins with a velocity of v= 15.5 m/s, and all of its kinetic energy Ek converts into potential energy Ep, thus we set Ep equal to Ek.
Because Ek is given by (1/2)*m*v², where m denotes mass and v represents speed, while Ep equals m*g*h, where m is mass, g is 9.81 m/s², and h is height. Now:

Ek=Ep 

(1/2)*m*v²=m*g*h, canceling out the mass,

(1/2)*v²=g*h, rearranging for height by dividing by g,

(1/2*g)*v²=h and substituting the values:

h=12.245 m. The hill's height rounded to the nearest tenth is h=12.25 m.

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3 months ago
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