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Nookie1986
2 months ago
9

A ski lift is used to transport people from the base of a hill to the top. If the lift leaves the base at a velocity of 15.5 m/s

and arrives at the top with a final velocity of 0 m/s, what is the height of the hill? Round the answer to the nearest tenth
Physics
2 answers:
Sav [3.1K]2 months ago
8 0
To make it straightforward for anyone looking for a quick answer while browsing, just enter 12.3
Yuliya22 [3.3K]2 months ago
5 0
This can be determined using the principle of energy conservation. The ski lift begins with a velocity of v= 15.5 m/s, and all of its kinetic energy Ek converts into potential energy Ep, thus we set Ep equal to Ek.
Because Ek is given by (1/2)*m*v², where m denotes mass and v represents speed, while Ep equals m*g*h, where m is mass, g is 9.81 m/s², and h is height. Now:

Ek=Ep 

(1/2)*m*v²=m*g*h, canceling out the mass,

(1/2)*v²=g*h, rearranging for height by dividing by g,

(1/2*g)*v²=h and substituting the values:

h=12.245 m. The hill's height rounded to the nearest tenth is h=12.25 m.

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