A ski lift is used to transport people from the base of a hill to the top. If the lift leaves the base at a velocity of 15.5 m/s

Answer:

Δx=(v+v0/2)t

Explanation:

We can determine which kinematic equation to apply by selecting the one that encompasses the known variables as well as the unknown we aim to solve for.

In this scenario, the unknown we wish to determine is the initial velocity v_0v

0

​  v, start subscript, 0, end subscript of the roller coaster.

Answer:

Refer to the explanation.

Explanation:

To grasp the concept, start with the fundamental idea of meniscus in a graduated cylinder.

"The meniscus refers to the curve noticed at the surface of a liquid due to its container. Depending on liquid surface tension and its adherence to the container’s walls, this meniscus may be concave or convex".

Given this definition, when measuring the volume of water, it's crucial to read the measurement at the bottom of the meniscus curve, as water forms a concave shape.

Taking the reading at eye level ensures an accurate volume, as it aligns with this method.

Additionally, this way of reading balances total pressure with atmospheric pressure by adjusting the cylinder's height to match the water level.

Answer:

a) W =400 kJ

b) W = 0 kJ

c) W =-160.944 KJ

Explanation:

Given

Process 1 ---> 2

Pressure at point (1) P1 = 10 bar = P2

Volume at point (1) V1 = 1 m^3

Volume at point (2) V2 =4 m^3

For Process 2 ---> 3, where V = constant

Pressure at point (3) P3 = 10 bar

Volume at point (3) V3 = 4 m^3

Process 3 ---> 1 defined as PV = constant.

Required

Sketch the processes on the PV coordinates To calculate the work in kJ

Work is calculated by W=

a=V2

b=V1

x=Pdx=dV

W=

a=V3

x=4dx=dV

W=400 kJFor Process 2 ---> 3

As V = constant in this case, the volume remains unchanged, resulting in W = 0 kJ  

For Process 3 ---> 1  By applying point (1) --> 5 x.2 = C ---> C = 1 P = 5V^-1  

a=V1

x=1V^-1dx=dVsubstituting values into this integral results in

  = -160.944 KJ