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sergey
12 days ago
8

0.0524 moles of H2O equals how many molecules of water?

Chemistry
2 answers:
lions [2.6K]12 days ago
8 0
Greetings!:

<span>Utilize Avogadro's constant:
</span>
1 mole -------------- 6.02*10²³ molecules
0.0524 moles -------- molecules of H2O

molecules of H2O = 0.0524* ( 6.02*10²³) / 1

  molecules of H2O = 3.15*10²² / 1

= 3.15*10²² molecules of H2O




lions [2.6K]12 days ago
8 0

Response:

Molec_{H_2O}=3.16x10^{22}MolecH_2O

Explanation:

Hello,

In this scenario, by applying Avogadro's number to relate moles to molecules, we find:

Molec_{H_2O}=0.0524molH_2O*\frac{6.022x10^{23}MolecH_2O}{1molH_2O} \\Molec_{H_2O}=3.16x10^{22}MolecH_2O

Best wishes.

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0.1045M represents the concentration of the initial sulfuric acid solution

Explanation:

Titration is conducted to ascertain the volume or concentration of an unknown electrolyte.

Given data:

acid volume = 50 ml

acid molarity =?

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molarity of NaOH = 0.1510

The titration formula applied is

Macid x Vacid = Mbase x Vbase

Substituting the values into the above equation results in:

Macid x 50 = 34.62 x 0.1510

Macid = \frac{5.22762}{50}

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Answer:

C

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29 days ago
Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.2845 g of co2 and 0.1451 g of h2o. wha
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CxHy + (x+0.25)O₂ → xCO₂ + 0.5yH₂O

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1 month ago
Why is it important to have regular supervision of the weight and measurements in the market
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Answer:

Oversight of weights and measures ensures correct evaluations of goods and services so that everyone receives a fair exchange in the marketplace. It also acts as a deterrent, promoting honesty among traders.

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1 month ago
he population of the Earth is roughly eight billion people. If all free electrons contained in this extension cord are evenly sp
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1) Drift velocity: 3.32\cdot 10^{-4}m/s

2. 5.6\cdot 10^{13} electrons per individual

Explanation:

1)

In a conducting material with an electric current, the drift velocity of electrons can be calculated using this equation:

v_d=\frac{I}{neA}

where

I stands for current

n represents the density of free electrons

e=1.6\cdot 10^{-19}C indicates the charge of an electron

A signifies the wire's cross-sectional area

The wire's cross-sectional area can be determined as

A=\pi r^2

where r denotes the wire's radius. Thus, the equation transforms to

v_d=\frac{I}{ne\pi r^2}

In this scenario, we have:

I = 8.0 A as the current

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So, the resulting drift velocity is:

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