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Natali5045456
2 months ago
8

How many SO32- ions are contained in 99.6 mg of Na2SO3? The molar mass of Na2SO3 is 126.05 g/mol.

Chemistry
2 answers:
Tems11 [2.7K]2 months ago
7 0
The total number of ions is calculated as follows: Starting with a mass of 99.6 mg, we convert this to grams: 99.6 mg = 0.0996 g. The conversion used is that 1 mg equals 0.001 g. The molar mass of Na2SO3 is 126.05 g/mole. We then determine the number of moles of Na2SO3. Next, we find the quantity of SO32- ions, considering that Na2SO3 dissociates to yield 2 moles of SO32- ions per mole of Na2SO3. Thus, knowing that one mole contains 6.022 x 10^23 ions, this translates to the resulting number of SO32- ions.
castortr0y [3K]2 months ago
6 0
99.6 mg = 0.0996 g. Using the conversion factors: 0.0996 g x (1 mol / 125.05 g) x (1 mol SO3 / 1 mol Na2SO3) x (6.02 x 10^22 / 1 mol SO3), the result is 4.79 x 10^19 SO32- ions.
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