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klemol
2 months ago
11

In regional spelling bee, the 8 finalists consist of 3 boys and 5 girls. Find the number of sample point the sample space S for

the number of possible orders at the conclusion of the contest for:
- All 8 finalist
- The fist 3 positions
Mathematics
1 answer:
PIT_PIT [12.4K]2 months ago
3 0

Answer:

i) A total of 40320 different arrangements

ii) For the initial 3 spots, there are 336 different combinations.

Step-by-step explanation:

Given: The total finalists = 8

The count of boys = 3

The count of girls = 5

To determine the number of sample point in the sample space S for possible arrangements, we calculate the factorial of 8!

The number of possible arrangements equals 8!

= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8

= 40320

ii) Among the 8 finalists, we must select the first 3 spots. The sequence matters, hence we utilize permutation.

nPr =\frac{n!}{(n - r)!}

Here n = 8 and r = 3

Substituting n = 8 and r = 3 into the formula, we arrive at

8P3 = \frac{8!}{(8 - 3)!}

= \frac{8!}{5!} \\= \frac{1.2.3.4.5.6.7.8}{1.2.3.4.5}

= 6.7.8

= 336

Thus, there are 336 different arrangements for the first 3 spots.

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