Answer:
14523.55J
Explanation:
The work exerted by the jogger against gravitational forces is represented by the following equation:
where m signifies mass, g represents gravitational acceleration taken as 
, and h denotes the elevation of the hill.
Given that the hill measures 132m in length and is inclined at an angle of 12 degrees to the horizontal, the height can be calculated as follows;
Substitute this value into equation (1) along with all other required parameters to arrive at the result;
Answer:
h = 1/50 v₀² g
Explanation:
This scenario illustrates conservation of momentum; the system comprises two bodies, hence forces during the collision are internal and momentum remains conserved.
Prior to the collision
po = 0 + (m/4) vo
Post collision
pf = (m + m/4) v
pf = (5m/4) v
m/4 vo = (5m/4) v
v = 1/5 vo
This indicates that after impact, the bodies travel at 1/5 of their initial velocity.
To determine the maximum height, we will apply the law of energy conservation.
At the peak post-collision
Em = K = ½ (5m / 4) v²
At the apex
Em = U = (5m/4) g h
½ (5m/4) v² = (5m/4) g h
h = ½ v² / g
h = ½ (1/5 v₀)² / g
h = 1/50 v₀² g
