Compare and contrast the strength of the forces between two objects with a mass of 1 kg each, a charge of 10

1 answer:

3 0

Let's explore the commonalities between the two forces: * They are proportional to the product of either mass or charge. * Their relationship to distance is inverse, meaning the forces weaken with the square of the distance. * Both forces are long-range, as a distance of zero does not exist up to infinity. Gravitational force is always attractive, while electric force can be either attractive or repulsive. Now, let's look at the distinctions: * The electric force is significantly stronger than the gravitational force. * The gravitational force is perpetually attractive, in contrast to the electric force, which can either attract or repel.

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State two advantages of a lead-acid accumulator over a leclanche cell

kicyunya [3294]

Respuesta:

Se pueden recargar.

Poseen una vida útil mayor.

Son reutilizables.

Explicación:

Las baterías de plomo-ácido y las pilas Leclanché son tipos de células electroquímicas.

Las pilas Leclanché son células primarias. Estas células producen reacciones químicas que generan corriente eléctrica de manera irreversible.

Por su parte, las baterías de plomo-ácido son células secundarias que permiten la reversibilidad de la corriente eléctrica generada.

Esto hace que las baterías de plomo-ácido sean reutilizables, con mayor durabilidad y un tiempo de vida más prolongado.

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4 months ago

A moving sidewalk 95 m in length carries passengers at a speed of 0.53 m/s. One passenger has a normal walking speed of 1.24 m/s

Maru [3345]

Answer: a) t = 1.8 x 10^2 seconds; b) t = 54 seconds; c) t = 49 seconds. Explanation: a) To determine the time of a stationary passenger on the sidewalk, we use the position formula. Given the constant speed of the walkway, we can calculate the time taken for set distances accordingly. This calculation extends into cases where combined velocities for walking are involved in subsequent queries.

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2 months ago

The acceleration of segment D is m/s2. Rank segments A, B , C from least accelerations to greatest acceleration. Least

Ostrovityanka [3204]

Answer:

D, C, B, A

Explanation:

The derivative from a velocity-time graph provides the acceleration value.

Segment A

$\frac{dy}{dx} = \frac{15m/s}{1s} = 15m/s^2$