One electron is involved. Explanation: In redox reactions, determining the equivalents requires knowledge of the number of transferred electrons. In this specific case, one equivalent corresponds to a transfer of a single electron.
84.34 grams of iron (III) chloride is the maximum produced since iron is the limiting reagent, and chlorine gas is in excess.
Explanation:
Balanced equation:
2 Fe + 3 Cl2 → 2 FeCl3
DATA PROVIDED:
iron = atoms
mass of chlorine = 67.2 liters
mass of FeCl3 =?
The number of moles of iron will be calculated as
number of moles = 
number of moles = 
number of moles = 0.52 mol of iron
moles of chlorine gas
number of moles = 
Substituting the values into the equation:
n = 
(molar mass of chlorine gas = 70.96 g/mol)
= 947.01 moles
As iron is the limiting reagent therefore
2 moles of Fe lead to 2 moles of FeCl3
0.52 moles of Fe will yield
= 
0.52 moles of FeCl3 is produced.
To express this in grams:
mass = n x molar mass
= 0.52 x 162.2 (molar mass of FeCl3 is 162.2g/mol)
= 84.34 grams
Response:
The mass percentage of a solution comprising 7.6 grams of sucrose and 83.4 grams of water equals 8.351 %.
Details:
Provided data:
Sucrose mass = 7.6 grams
Water mass = 83.4 grams
In this scenario, sucrose acts as the solute, while water is the solvent.
The calculation for mass percent of a solution is done using the following formula:
Mass percent = (Mass of Solute/Mass of Solution)(100)
As sucrose is the solute, the mass equals 7.6 grams.
The total mass of the solution, which includes both sucrose and water, comes out to:
Total mass = 7.6 grams + 83.4 grams = 91 grams
Therefore, applying the values gives mass percent = (7.6/91)(100) = 8.351 %.
The pH level is 1.39. To explain, we start with the given information: the concentration of HClO is 0.15 M, with an acid dissociation constant of 2.9 × 10-8. The objective is to calculate the pH of the solution. Through the process, we find that the equilibrium concentration after applying the formula yields 0.04069 M for H3O⁺, leading us to a pH of 1.39.
d is your answer; I hope this assists you.
