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timurjin
9 days ago
7

II. Pure magnesium metal is often found as ribbons and can easily burn in the presence of oxygen. When 3.86 g of magnesium ribbo

n burns with 155ml of oxygen at 1.0 atm and 275 K , a bright, white light and a white, powdery product is formed, magnesium oxide. How many grams of excess reactant remain?
Chemistry
1 answer:
Alekssandra [3K]9 days ago
5 0
Hello, in this situation, the chemical reaction occurring is as follows: Next, we will ascertain the limiting reactant by calculating the moles of magnesium oxide produced from 3.86 g of magnesium and 155 mL of oxygen using the given mole ratios of 2:1:2 and applying the ideal gas equation, demonstrating that oxygen is the limiting reactant because it generates the least magnesium oxide. Subsequently, we determine the mass of magnesium consumed solely by the oxygen.
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When double-stranded DNA is heated at neutral pH, which change does not occur?
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Answer:

Option B) The N-glycosidic bond that forms between the base and the pentose breaks

Explanation:

When the forces that hold the two strands of DNA together are compromised, they separate. This process is identified as denaturation.

The critical forces maintaining the dual strands of DNA are the hydrogen bonds (physical forces) linking base pairs (Adenine with Thymine, and Guanine with Cytosine).

Denaturation is a phenomenon that can be induced by various factors: alterations in pH, introduction of salt, heating, and others.

When a DNA solution undergoes heating, the denaturation process can be monitored through UV absorption (typically at a wavelength of 260 nm): UV light absorption is minimal when the DNA (double-stranded) is in its native state, as the nitrogenous bases are stacked like coins, resulting in less light absorption.

As the DNA double helix unwinds during denaturation, these bases become exposed, leading to an increase in UV absorption.

Additionally, viscosity is another method to observe DNA denaturation: in a double-stranded DNA solution, viscosity is high due to the stiffness of the double chain; however, once the strands separate, the viscosity decreases (as time progresses with heating).

Ultimately, during the heating process, only physical forces are disrupted (i.e., hydrogen bonds), while chemical bonds (such as covalent bonds) remain intact, which would require extreme conditions for disruption.

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25 days ago
Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that
KiRa [2933]

Answer: The required mass of KNO₃ is, 1.08\times 10^2g

Explanation: Provided,

Molal-freezing-point-depression constant (K_f) for water = 1.86^oC/m

Amount of water = 275 mL

Molar mass of KNO₃ = 101.1 g/mole

First, we need to determine the mass of the water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

Density of water = 1.00 g/mL

\text{Mass of water}=1.00g/mL\times 275mL=275g=0.275kg

Next, we will figure out the mass of KNO₃

Formula utilized:

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of }KNO_3}{\text{Molar mass of }KNO_3\times \text{Mass of water in Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -14.5^oC

\Delta T^o = freezing point of water = 0.0^oC

i = Van't Hoff factor = 2  (for KNO₃ electrolyte)

K_f = freezing point constant for water = 1.86^oC/m

m = molality

Substituting all known values into this equation yields

0.0^oC-(-14.5^oC)=2\times (1.86^oC/m)\times \frac{\text{Mass of }KNO_3}{101.1g/mol\times 0.275kg}

\text{Mass of }KNO_3=108.369g=1.08\times 10^2g

Consequently, the mass of KNO₃ that must be added is, 1.08\times 10^2g

4 0
1 month ago
How many significant figures in 8400
castortr0y [3046]
The number 8400 has two significant figures.
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A solid mixture weighs 0.6813 g. It contains gallium bromide (GaBr3) and other inert impurities. When the solid mixture was diss
castortr0y [3046]

Answer:

The mass percentage of GaBr₃ in the solid mixture is 30.2 %.

Explanation:

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To find the molar mass, we have: MW GaBr₃ = 309.4 g/mol and MW AgBr = 187.8 g/mol.

Using these values, we note that 187.8 g of AgBr corresponds to 1 mol.

If 0.368 g of AgBr yields x moles, we calculate x to be 2.0 x 10⁻³ mol AgBr.

Based on the stoichiometry, 1 mol of GaBr₃ produces 3 mol of AgBr, giving us:

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Relating this to the total mass:

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12 days ago
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