A student adds 10.00 mL of a 2.0 M nitric acid solution to a 100.00 mL volumetric flask. Next, 50.00 mL of a 0.00500 M solution

Hello!

density = 2.67 g/cm³

volume = 30.5 mL

Thus:

Mass = density * volume

Mass = 2.67 * 30.5

Mass = 81.435 g 

I predict that there will be an increase in the seconds recorded in the time column. This is because, as more water is mixed with sodium thiosulfate, its concentration diminishes in each flask. Additionally, a lower concentration results in a slower reaction rate since fewer molecules of sodium thiosulfate means there are less frequent collisions with sulfuric acid. With fewer collisions occurring in the reaction, it takes a longer time for the reaction to complete, leading to increased time when sodium thiosulfate is diluted.

Explanation:

I can confirm that this explanation is accurate.

d is your answer; I hope this assists you.

The enthalpy change in this scenario totals 7.205 KJ. The task is to compute the enthalpy variation during the conversion of 10.0 g of ice at -25.0°C into water at 80.0°C, factoring in specific heats and enthalpy for phase transitions.

Answer:

Unfavorable reactions include Reaction A and Reaction B.

Favorable coupled reactions: Reactions B with C and Reactions A with C.

Net energy change:

For Reactions B and C: -14.2 kJ/mol

For Reactions A and B: 30.1 kJ/mol

For Reactions A and C: -16.7 kJ/mol

Explanation:

A reaction is considered thermodynamically favorable (or spontaneous) if ΔG is less than 0. Thus, the unfavorable reactions where -ΔG is greater than 0 are:

Reaction A and Reaction B.

In coupling Reaction C with Reaction B and Reaction A, the following equation is obtained:

ATP + fructose-1,6-phosphate ⟶ ADP + fructose-1,6-bisphosphate

ΔG equals 16.3 minus 30.5, resulting in -14.2 kJ/mol.

For the reaction ATP + glucose ⟶ ADP + glucose-6-phosphate, ΔG equals 13.8 minus 30.5, yielding -16.7 kJ/mol.

Overall, the coupled reaction of A and B results in a change of free energy of:

ΔG = 13.8 plus 16.3, which equals 30.1 kJ/mol.