The density of air under ordinary conditions at 25°C is 1.19 g/L. How many kilograms of air are in a room that measures 10.0 ft

Question

17 days ago

9

× 11.0 ft and has an 10.0 ft ceiling? 1 in = 2.54 cm (exactly); 1 L = 103 cm3.

2 answers:

Tems11 [846] · Answer 1 · 2026-02-16T16:04:32+03:00

Answer: The quantity of air in the room is approximately 37 kg.

Explanation:

The volume of a rectangular room is found with the formula:

$V=lbh$

where l = 11 ft, b = 10 ft, h = 10 ft.

Applying values,

$V=10\times 11\times 10=1100ft^3=1100\times 28.3L=31130L$ (with conversion factor $1ft^3=28.3L$ )

Mass is determined by:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Given density of air is 1.19 g/L and volume equals 31,130 L.

Calculating mass,

$1.19g/L=\frac{\text{Mass of air}}{31130L}\\\\\text{Mass of air}=37000g=37.0kg$ (remembering 1 kg = 1000 g)

Therefore, the mass equals about 37 kg of air.

alisha [964] · Answer 2 · 2026-02-16T16:03:18+03:00

Answer: The air in the room weighs 37.068 kg

Explanation:

Given dimensions:

Length = 10.0 ft

Width = 11.0 ft

Height = 10.0 ft

The volume of the room (rectangular prism) is calculated using:

$V=lbh$

where l = length, b = breadth, h = height.

Substituting the values,

$V=10.0ft\times 11.0ft\times 10.0ft=1100ft^3=31148.53L$

Using the conversion: $1ft^3=28.3168L$

Next, calculate the mass of the air based on density:

$Density=\frac{Mass}{Volume}$

$1.19g/L=\frac{Mass}{31148.53L}$

$Mass=37066.7507g=37.068kg$

Conversion: 1 kg = 1000 g

Thus, the air mass in the room equals 37.068 kilograms.