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zalisa
1 month ago
13

What is the mass of nickel(ii) nitrate (182.71 g/mol) dissolved in 25.0 ml of 0.100 m ni(no3)2 solution?

Chemistry
2 answers:
KiRa [2.9K]1 month ago
8 0
The mass of nickel(II) nitrate amounts to 0.4568 grams. Given the molar mass of nickel(II) nitrate is 182.71 g/mole, its volume is 25.0 ml, and the molarity is 0.100 M. Molarity is defined as the mass of solute present in one liter of solution. The utilized formula is: w = mass of nickel(II) nitrate, M = molar mass, V = volume of solution. Inputting the known values into the formula yields the result: 0.4568 grams of nickel(II) nitrate.
alisha [2.9K]1 month ago
4 0
To determine the amount of ni(NO3)2 that dissolved in 25.0 ml of 0.100m ni(NO3)2 solution, the following calculations apply: Calculate the number of moles = molarity x volume in liters = 25 x 0.100/1000 = 2.5 x 10^-3 moles. Then, mass = number of moles x molar mass = 2.5 x 10^-3 moles x 182.71 g/mol = 0.457 grams.
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E = mc²

where E = energy produced

m = mass of the nucleus

C = speed of light

m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg

C = 3 x 10⁸ m/s, thus C² = 9 x 10¹⁶

E = 1.37 x 10⁻¹² J

7 0
2 months ago
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32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?
alisha [2963]
At standard temperature and pressure, it is established that 1 mole of gas has a volume of 22.4 liters.

According to the periodic table:
the molar mass of oxygen is 16 g
and the molar mass of hydrogen is 1 g
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Thus, 18 g of water occupies 22.4 liters, therefore:
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5 0
2 months ago
Samples of three different compounds were analyzed and the masses of each element were determined. Compound Mass N (g) Mass O (g
Anarel [2989]

The correct answer is: c. N2O, N2O4, N2O5.

According to the law of multiple proportions, also referred to as Dalton's Law, when two elements form compounds, the mass ratios of the second element that combine with a specific mass of the first yield small whole number ratios.

1) For NO, the mass ratio m(N): m(O) is 14: 16, simplified to 7: 8.

2) In N₂O, the ratio m(N): m(O) equates to 2·14: 16, which simplifies to 7: 4.

3) For NO₂, the masses yield m(N): m(O) = 14: 2·16, simplifying to 7: 16.

4) In N₂O₅, the ratio is (2·14): (5·16), which simplifies to 7: 20.

5) For NO₄, the mass ratio is m(N): m(O) = 14: (4·16), which simplifies to 7: 32.

6) N₂O₄ gives a ratio of m(N): m(O) as (2·14): (4·16), simplifying to 7: 16.

A) This means m(N): m(O) = 5.6 g: 3.2 g, simplifying results in 1.75: 1, which further translates to m(N): m(O) = 7: 4.

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C) Lastly, for m(N): m(O) = 1.4 g: 4.0 g, then adjustments yield a ratio of m(N): m(O) = 7: 20.

6 0
3 months ago
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