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Nesterboy
3 months ago
15

Water is made of two hydrogen atoms and one oxygen atom bonded together. Julia is describing how water undergoes a physical chan

ge when it boils. She says that the particles shift to be farther apart and that the oxygen and hydrogen separate. She also says that the total mass of the steam is the same as the initial water, and that heat energy was required to cause the change. She finishes her description by saying that the steam can be turned back into water if it is cooled
Physics
2 answers:
kicyunya [3.2K]3 months ago
8 0
Steam transforms into gas as it escapes into the atmosphere. Even if you manage to capture the steam as it ascends, it can revert to H2O when it cools down. Due to the evaporation process, the final volume of water will differ from the original amount.
Maru [3.3K]3 months ago
7 0
C is the correct selection; trust me, it's not B or A.
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A wave travels through a medium because
Maru [3345]

if you want the short reply, the answer is B

5 0
2 months ago
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A bucket of mass m is hanging from the free end of a rope whose other end is wrapped around a drum (radius R, mass M) that can r
Maru [3345]

Response:

Explanation:

Let T denote the tension.

By employing Newton's second law to analyze the bucket's downward motion, we have:

mg - T = ma

A torque, TR, acts on the drum, inducing an angular acceleration α in it. If I refers to the moment of inertia of the drum, then:

TR = Iα

Rearranging gives: TR = Ia/R

This leads to T =  Ia/R²

Substituting this expression for T back into the previous equation yields:

mg - T = ma

mg - Ia/R² = ma

Consequently, we find that mg =  Ia/R² + ma

Therefore, a (I/R² + m) = mg

This results in: a = mg / (I/R² + m)

Next, we aim to express T as:

mg - T = ma

which simplifies to mg - ma  = T

Rearranging gives mg - m²g / (I/R² + m) = T

Thus, we arrive at: mg - mg / (1 + I / m R²) = T

For part (b), T =  Ia/R²

and for part (c), the moment of inertia of a hollow cylinder calculates to:

I = 1/2  M (R² - (R² / 4))

This simplifies to 3/4 x 1/2 MR², yielding 3/8 MR²

Thus, I / R² = 3/8 M

When we substitute, we find a = mg / (3/8 M + m)

and subsequently T =  Ia/R²

= 3/8 MR² × mg / (3/8 M + m) × 1/R²

Results in: \frac{3mMg}{(3M +8m)}

7 0
2 months ago
The use of air bags in cars reduces the force of impact by a factor of 110.(The resulting force is only as great.) What can be s
Keith_Richards [3271]
The change in momentum (i.e., impulse) from the car during the collision remains constant regardless of whether an airbag is present. This is because the car's mass is unchanged, and the velocity change remains the same. Therefore, if the force is constant as F and reduced by a factor of 110, it follows that the collision duration must increase by the same factor when the airbag is utilized.
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2 months ago
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