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11 days ago

A student sits motionless on a stool that can turn friction-free about its vertical axis (total rotational inertia I). The stude

nt is handed a spinning bicycle wheel, with rotational inertia I1, that is spinning about a vertical axis with a counterclockwise rotational velocity ω0. The student then turns the bicycle wheel over (that is, through 180∘). Determine the final rotational velocity acquired by the student. Express your answer in terms of the variables

Physics

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A friend tosses a baseball out of his second floor window with initial velocity of 4.3m/s(42degrees below the horizontal). The b

Keith_Richards [3271]

<span>Part b) Find your horizontal distance from the window (answer: 1.5 m)
Part c) Calculate the speed of the ball upon catching it (answer: 8.2 m/s)

I'm confused about what "42 degrees below the horizontal" means. Could someone provide guidance on how to approach this?</span>

7 0

2 months ago

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In space, astronauts don’t have gravity to keep them in place. That makes doing even simple tasks difficult. Gene Cernan was the

Keith_Richards [3271]

Newton's First Law: A body remains in its current state of motion or at rest unless a force acts upon it.

Newton's Second Law: Motion changes are proportional to the applied force and oriented in the same direction.

Newton's Third Law: Every action has a corresponding and opposite reaction.

Tasks that would be challenging to perform in orbit include:

-operating a valve

-navigating on foot

-attempting to take a shower

-remaining still

4 0

2 months ago

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A 5 kg block moves with a constant speed of 10 ms to the right on a smooth surface where frictional forces are considered to be

Yuliya22 [3333]

Answer:

The work done, W = 19.6 J

Explanation:

It’s provided that

The mass of the block, m = 5 kg

The velocity of the block, v = 10 m/s

The coefficient of kinetic friction between the block and rough surface is 0.2

Distance traveled by the block, d = 2 m

As the block traverses the rough section, it loses energy equal to the work done by the kinetic energy.

$W=\mu_kmgd$

$W=0.2\times 5\times 9.8\times 2$

W = 19.6 J

Thus, the change in kinetic energy of the block moving through the rough section is 19.6 J. Consequently, this is the required answer.

5 0

2 months ago

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A hard rubber rod with an electric potential energy of 5.2 × 10–3 J has a charge of 4.0 µC at the tip. What is the electric pote

Keith_Richards [3271]

1) The electric potential energy can be defined as the product of the electric potential and the associated charge:
$U=q V$
where
q refers to the charge
V denotes the electric potential

In this scenario, the charge on the rod is $q=4.0 \mu C = 4.0 \cdot 10^{-6}C$ , and the potential energy is $U=5.2 \cdot 10^{-3} J$ , thus we may rearrange the earlier formula to find the electric potential at the tip:
$V= \frac{U}{q}= \frac{5.2 \cdot 10^{-3}J}{4.0 \cdot 10^{-6} C}=1300 V=1.3 \cdot 10^3 V$

2) Using this same formula, if the charge changes to $q=2.0 \mu C = 2.0 \cdot 10^{-6} C$ , the resulting electric potential will be:
$V= \frac{U}{q}= \frac{5.2 \cdot 10^{-3} J}{2.0 \cdot 10^{-6}C}=2600 V = 2.6 \cdot 10^{3}V$

8 0

2 months ago

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