The table lists the lattice energies of some compounds. Compound Lattice Energy (kJ/mol) LiF –1,036 LiCl –853 NaF –923 KF –821 N

Answer: 0.0007 moles of are released when the temperature rises.

Explanation:

To determine the moles, we utilize the ideal gas law, as follows:

where,

P = gas pressure = 1.01 bar

V = gas volume = 1L

R = gas constant =

• Calculated moles at T = 20° C

The gas temperature = 20° C = (273 + 20)K = 293K

Substituting values into the equation gives:

• Calculated moles at T = 25° C

The gas temperature = 25° C = (273 + 25)K = 298K

Substituting values into the equation gives:

• Released moles =

Therefore, 0.0007 moles of are released when the temperature increases from 20° C to 25° C.

Answer:

0.20M of nitric acid

0.00250M of KSCN

Explanation:

In the case of nitric acid, the solution's dilution changes from 10.00mL to 100.00mL, resulting in a 1/10 dilution. Given the original concentration of nitric acid is 2.0M, the updated concentration becomes: 2.0M×(1/10)=0.20M of nitric acid

Similarly, the dilution of KSCN extends from 50.00mL to 100.00mL, equal to a 1/2 dilution. Consequently, the new concentration of KSCN turns out to be:

0.00500M × (1/2) = 0.00250M of KSCN

I hope it aids you!

Hello!

To find [H₃O⁺], we will employ the Henderson-Hasselbalch equation, as this involves an acid and its conjugate base:





Next, we derive [H₃O⁺] using the definition of pH:





Hence, the concentration of [H₃O⁺] comes out to be 0.00014 M

Wishing you a good day!

Answer:

0.133

Explanation:

The reaction that occurs between KIO3 and KI in an acidic medium is described as

IO3⁻ +5I⁻ +6h⁺ → 3I₂ + 3H₂O

I₂ subsequently reacts with sodium thiosulfate

NaS₂O₃  → 2Na⁺ + S₂O₃²⁻

The overall reaction can be summarized as

IO⁻₃ + 6H⁺ + 6S₂O₃³⁻ → I⁻ + 3S₄O₆²⁻ + 3H₂O

The mole of KIO₃

is computed using molarity multiplied by volume

which equals 0.00002mol

One mole of KIO₃ reacts with 6 moles of S₂O₃²⁻

which gives 2x6x10⁻⁵

To find concentration,

= 0.133m