n the table below, write the density of each object. Then predict whether the object will float or sink in each of the fluids. W

In the case of a 100m Race, displacement equals the distance traveled. If we divide this equation by the time t (assuming t represents the time taken to finish the 100m race), we derive that velocity equals speed. Conversely, in a 400m race where a full lap is completed, the racer’s starting and ending positions overlap, leading to displacement equaling 0, while the distance is not zero (400m). Therefore, it follows that displacement does not equal distance, leading to the conclusion that velocity does not equal speed.

Answer:

• Please refer to the attached image for the graph with labeled axes and points.

Explanation:

This is a guide to fulfilling the instructions along with essential notes for understanding how to create such graphs:

1) The horizontal axis should indicate pressure ranging from 0 mb to 760 mb, while the vertical axis corresponds to volume ranging from 0 to 1 mL.

The x-axis captures the independent variable, and the y-axis records the dependent variable. Both axes must be accurately labeled, showing the variable names and their respective units.

In this context, the origin, (0,0), signifies the intersection of the axes at a pressure of 0 mb and a volume of 0.0 milliliters.

2) Allocate values for the divisions on the axes to maximize the usage of space on both.

An effective graph aims to utilize the entire space on both axes; for this, identify the maximum values for pressure and volume, and determine the corresponding marks.

The pressure range along the x-axis is [90, 760 mb], suggesting large divisions of 100 mb, with the farthest right mark at 800 mb. You can then subdivide each 100 mb interval into 10 smaller sections, using small divisions of 10 mb (my example employs 4 sections of 25 mb, but 10 mb is preferable).

The volume's range for the vertical axis is [0.1, 0.8], so it’s best to use divisions set at 0.1 ml.

3) Next, identify and label the points as follows:

• (90, 0.9) ⇒ 90 mb, 0.9 ml

• (100, 0.8) ⇒ 100 mb, 0.8 ml

• (400, 0.2) ⇒ 400 mb, 0.2 ml

• (600, 0.15) ⇒ 600 mb, 0.15 ml

• (760, 0.1) ⇒ 760 mb, 0.1 ml

The points represented as (x, y) are referred to as ordered pairs, indicating that the sequence is significant: the first number denotes the independent variable whereas the second denotes the dependent variable.

Thus, for the point (90, 0.9), 90 indicates a pressure of 90 mb and 0.9 indicates a volume of 0.9 ml.

To find (600, 0.15), since the horizontal increments are valued at 0.1, you should place the second coordinate of the point between the marks corresponding to 0.1 and 0.2 ml.

This allows you to accurately plot each point on the graph.

Answer:

The correct choice for your inquiry is option A, Argon.

Explanation:

Isotope               Atomic mass                      Percent (%)

    1                       35.9675                              0.337

    2                      37.9627                              0.063

    3                      39.9624                            99.6

To calculate the average atomic mass: (Mass of isotope 1)(percent of 1) + (Mass of isotope 2)(percent of 2) + (Mass of isotope 3)(percent of 3)

Average atomic mass = (35.9675)(0.00337) + (37.9627)(0.00063) + (39.9624)(0.996)

Average atomic mass = 0.1212 + 0.0239 + 39.8025

Average atomic mass = 39.9476

                   Theoretical  Atomic mass

a) Ar                         39.95

b) K                          39.10

c) Cl                         35.45

d) Ca                       40.08

                 

Response:

Clarification:

Hello,

In this scenario, since a single drop equates to 0.05 mL of the solution provided, with a concentration of 0.02 g/mL, the mass of oleic acid in one drop calculates to:

Best wishes.

The change in temperature can be expressed as:

By substituting in the known values, we arrive at:

Thus, we obtain the required answer.