What precisely is being followed here?
<span>BaCl2 + Na2SO4 --> BaSO4 + 2NaCl
In this reaction, 1.0 g of BaCl2 and 1.0 g of Na2SO4 are present. We need to identify the limiting reactant.
"First, convert grams to moles"
1.0 g BaCl2 * (1 mol BaCl2 / 208.2 g BaCl2) = 4.8 x 10^-3 mol BaCl2
1.0 g Na2SO4 * (1 mol Na2SO4 / 142.04 g Na2SO4) = 7.0 x 10^-3 mol Na2SO4
(7.0 x 10^-3 mol Na2SO4 / 4.8 x 10^-3 mol BaCl2) = 1.5 mol Na2SO4 per mol BaCl2
"Using this ratio to compare with the balanced equation, BaCl2 + Na2SO4 --> BaSO4 + 2NaCl"
The balanced equation indicates that 1 mol of BaCl2 reacts with 1 mol of Na2SO4. However, we found that 1.5 mol of Na2SO4 is available for each mol of BaCl2. Therefore, BaCl2 is the limiting reagent.</span>
Answer:
Explanation:
The percent composition indicates the mass percentage of a specific element within the compound.
The chemical formula for chromium(III) nitrate is 
.
The molar mass for chromium(III) nitrate is calculated at 238.011 g/mol.
Each mole of chromium(III) nitrate includes 9 moles of oxygen.
The molar mass of oxygen is 16 g/mol.
Hence, Mass = Molar mass * Moles = 16 * 9 g = 144 g.
Response:
I think it should be 24 hours.
Details:
[H3O+][OH-] = 4.5 x 10^-15
[H3O+] = [OH-] = 6.7 x 10^-8 M
Explanation: perform the calculation
