Utilize the ideal gas law:
n = PV / RT
P = 100kPa = 100 x 1000 x (9.8 x 10^{-6}) = 0.98 atm
Convert kPa to atm, where 1 Pa = 9.8 x 10^{-6} atm.
T = 293 K
V = 6.8 L
R = 1/12
Substituting all values leads to:
n = 0.272
Answer:
C) 1.15 × 10⁻⁷ mm
Explanation:
Step 1: Provided information
Average separation between oxygen and nitrogen atoms: 115 pm
Step 2: Change the distance to meters (SI standard unit)
Using the conversion 1 m = 10¹² pm.
115 pm × (1 m/10¹² pm) = 1.15 × 10⁻¹⁰ m
Step 3: Transform the distance to millimeters
Employing the conversion 1 m = 10³ mm.
1.15 × 10⁻¹⁰ m × (10³ mm/1 m) = 1.15 × 10⁻⁷ mm
Answer:
The process of converting glucose to glucose-6-phosphate is an endergonic reaction, which is coupled with the exergonic hydrolysis of ATP.
Explanation:
Within glycolysis, the phosphorylation of glucose to glucose-6-phosphate occurs first, facilitated by the hexokinase enzyme. This reaction is endergonic. This phosphorylation is a coupled reaction tied to ATP hydrolysis, where the free energy released by ATP hydrolysis drives glucose phosphorylation.
1) Chromium(III) nitrate is classified as acidic because it is derived from a weak base (chromium(III) hydroxide Cr(OH)₃) and a strong acid (nitric acid HNO₃). 2) Sodium hydrosulfide is considered basic because it results from a strong base (sodium hydroxide NaOH) and a weak acid (hydrogen sulfide H₂S). 3) Zinc acetate is slightly basic since zinc hydroxide (Zn(OH)₂) is a stronger base than acetic acid (CH₃COOH).
An r-selected species has a significantly faster reproductive rate compared to K-selected species.
The focus of r-selected species is on quick maturation and reproduction. They are likely to breed during short periods when water supply is available, thus enhancing their survival chances.
Conversely, K-selected species prioritize nurturing their young and tend to reproduce later. Due to the longer maturation time before breeding, by the time K-selected species are ready, the water supply may be depleted, leading to lower survival odds.
Hope this clarifies!
If you have more questions, don’t hesitate to ask! Have a fantastic day!:)
~Collinjun0827, Junior Moderator
