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dezoksy
2 months ago
8

You want to test the effect of pH on the distribution of Artemia in your 35cm long testing chamber. If you measure a pH = 1 at o

ne end of the chamber and a pH = 13 at the other end, and the gradient distribution along the testing chamber is linear, what would you predict the pH to be 10 cm from the most acidic end?
Chemistry
1 answer:
Tems11 [2.7K]2 months ago
7 0

Answer:The pH measured 10 cm from the most acidic end is 3.42.

Explanation:

The pH at one end = 1The pH at the other end = 13

The chamber length = 13 cm

The change in pH concerning the chamber's length from the acidic end is

Thus, the pH at a distance of 10 cm from the most acidic end is 3.42.

x=\frac{13-1}{35 cm}=\frac{12}{35} pH/cm

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The two-slit diffraction experiment shows how light can be treated as particles and how light waves carry the statistical inform
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The double-slit experiment serves as a renowned method to exemplify concepts in quantum mechanics. Specifically, it highlights the idea of wave-particle duality. Employing a light wave shows diffraction and interference, which are typical characteristics of wave behavior. Unexpectedly, using an electron beam produces an interference pattern as well, indicating that electrons can exhibit wave-like properties.


Explanation:

The optical phenomenon would nearly resemble, yet be entirely distinct from, that involved with the exploitation of light. Interference and diffraction are the characteristics distinguishing waves from particles: waves can interfere and disperse, whereas particles cannot.

Light curves around obstacles akin to waves, and this bending results in the single-slit diffraction pattern.

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2 months ago
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The following five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt), were found on a lab
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Answer:

Please review the following responses

Explanation:

1) A solution of 100. mL contains 19.5 g of NaCl  (3.3M)

2) 100. mL of NaCl solution at 3.00 M (3 M)

3) A solution of 150. mL holds 19.5 g of NaCl  (2.2 M)

4) The concentrations of beakers 1 and 5 are identical (1.5M)

Molar mass of NaCl = 23 + 36 = 59 g

For beaker number 3:

          59 g -------------- 1 mol

           19.5 g -------------   x

  x = 19.5 x 1/59 = 0.33 mol

Molarity (M) = 0.33 mol/0.150 l = 2.2 M

For beaker number 4:

Molarity (M) = 0.33mol/0.10 l = 3.3 M

For beaker number 5:

Molarity (M) = 0.450/0.3 = 1.5 M

4 0
2 months ago
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Why did you blank with the 0.0020 M Fe(NO3)3 solution as opposed to just DI water? What does it do to your spectrum? What chemic
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Response:

The cuvette was prepared with the solution so that the spectrometer measures solely the absorbance from the solute. This also means the spectrometer disregards other fluctuations in absorbance that typically arise from the composition of water. The spectrometer focused only on the absorbance of FeNCS^{2+} as reflected in the spectrum. The reaction between the Fe^{3+} and the SCN^{-} produces two clear liquids that generate the orange product FeNCS^{2+} which leads to the absorbance spectrum. Due to the orange color of the solution, it reflects this hue and others like it, while absorbing blue tones. To isolate the absorption of just the FeNCS^{2+}, pre-rinsing the cuvette with the solutions intended for measurement is advisable, along with using a kimwipe to clean any fingerprints that might impact data collection.

Clarification:

The cuvette was prepared with the solution so that the spectrometer measures solely the absorbance from the solute. This also means the spectrometer disregards other fluctuations in absorbance that typically arise from the composition of water. The spectrometer focused only on the absorbance of FeNCS^{2+} as reflected in the spectrum.

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1 month ago
How many electrons are involved in one equivalent of oxidation-reduction?
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3 0
2 months ago
Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d
KiRa [2933]

Response: k = 23045 N/m

Clarification:

To determine the spring constant, one must consider the maximum elastic potential energy that the spring can withstand. The kinetic energy of the vehicle should equal at minimum the elastic potential energy of the spring when it is fully compressed. Hence, we express it as:

K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2    (1)

M: mass of the vehicle = 1050 kg

k: spring constant =?

v: car speed = 8 km/h

x: maximum spring compression = 1.5 cm = 0.015m

You need to resolve equation (1) for k. Beforehand, convert the speed v to meters per second:

v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}

k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}

The spring constant calculates to 23045 N/m

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2 months ago
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