The responses would be:
C. Bubbles form
E. There is a change in color
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While the chosen answers are indicative of chemical reactions, if you are solely referring to the chemical reaction in your example, these two answers represent the only options.
A chemical reaction occurs when reactants create a new substance. Indicators of a chemical reaction include alterations in smell, color, and temperature. At times, precipitates may develop.
x = 4,138 m. In this problem, we invoke the rotational equilibrium equation. Fixing our reference on the left-side pivot establishes the positive direction for counterclockwise rotation: ∑ τ = 0, leading to formulas where x = (-WL/2 + 4n₂) / W_woman. Converting to SI units where M = 2.72 kg and M_woman = 59.09 kg, and establishing equilibrium equations yields n₁ + n₂ = (2.72 + 59.09) 9.8. In cases where the system initiates rotation, n₁ equals 0, thus finding n₂ = 605,738 N. Calculation for x gives 4,138 m.
Inertia = inactivity
The element that influences an increase in inertia is "mass." The greater the mass of an object, the more inertia it possesses.
D) Both perform no work
Explanation:
The work accomplished by a force is defined as:
where
F represents the applied force
d denotes the displacement
is the angle highlighted between the applied force and the displacement vector
From this formula, it is clear that work is only done when displacement occurs, meaning the object has to move.
In this instance, as the wall is unmoving, the displacement is zero: d = 0, thus no work is performed.
Answer:
A) 5.1*10^10m B) 5.4*10^6m
Explanation:
Utilizing the formula for surface radiation P (energy per second in Watts) = emissivity constant * surface area * Stefan-Boltzmann constant * Temperature in Kelvin^4 *
2.7*10^31 = 1* 5.67*10^-8*A*11000^4
Rearranging to solve for A = 2.7*10^31 / (5.67*10^-8*1.46*10^16) = 0.3261*10^23m^2
Assuming the shape is spherical, the surface area is = 4πR^2 (radius of Rigel)
R = √(0.3261*10^23 / 4*π) = 5.1 * 10^10m
B) repeating the same calculation
2.1 *10^23 = 1*A*5.67*10^-8*10000^4 where A is the surface area of Procyon
Rearranging gives A = 2.1*10^23/(5.67*10^-8*10^16)
A = 0.37*10^15
Assuming the star is spherical;
A = 4πR^2 where R is Procyon's radius
R = √(0.37*10^15/4π) = 5.4*10^6m
