H+ ( aq ) + HCO3- ( aq ) ------> H2O( l ) + CO2 ( g ) The overall reaction when hydroiodic acid interacts with sodium hydrogen carbonate is: HI + NaHCO3 ----> NaI + H2O + CO2. The net reaction shows H2CO3’s instability, leading it to dissociate into water and carbon dioxide found in the reactants. In this reaction, H2CO3 also referred to as carbonic acid, is complemented by iodine and sodium from the reactants, creating NaI in the products. Including the physical states, the balanced equation reads: HI ( aq ) + NaHCO3 ( aq ) ----> NaI ( aq ) + H2O ( l ) + CO2 ( g ). The complete ionic equation represents each compound as ions in the aqueous phase: H+ ( aq ) + I- ( aq ) + Na+ ( aq ) + HCO3- ( aq ) -------> Na+ ( aq ) + I- ( aq ) + H2O( l ) + CO2 ( g ). In this reaction, the spectator ions are I- and Na+, allowing for their cancellation which leads to the net ionic equation: H+ ( aq ) + HCO3- ( aq ) ------> H2O( l ) + CO2 ( g ). Hope that helps!
Answer:
For the equation of nuclear transmutation, the answer is Option A. 1 0n
Explanation:
Further details on balancing the equation for the reaction presented in the question can be found in the accompanying image.
For 1.000 g of X, the mass of Y is 0.1621 g. The mass ratio of Y = 2.100 g: 0.1621 g equals 1:0.07. For 1.000 g of X, the mass of Y is 0.7391 g, which leads to a mass ratio of Y = 2.100 g: 0.7391 g simplifying to 1:0.35 or 20:7. For 1.000 g of X, the corresponding mass of Y is 0.2579 g, yielding a mass ratio of Y = 2.100 g: 0.2579 g resulting in 1:0.12. For 1.000 g of X, the mass of Y becomes 0.2376 g, giving a mass ratio of Y = 2.100 g: 0.2376 g, simplifying to 1:0.11. Lastly, for 1.000 g of X, the mass of Y is determined to be 0.2733 g, leading to a mass ratio of Y = 2.100 g: 0.2733 g which reduces to 1:0.13. Among the calculated values, option B aligns most closely with the law of multiple proportions.
