Answer:
The result is "4,241.17 years"
Explanation:
The disintegration rate for C-14 atoms is indicated in
The dissolution rate of the sample is given by
The C-14 proportion within the sample can be determined as per
With a half-life of 5730 years.
Now, we need to compute the number of half-lives (n) that are applicable:
Thus, the age of the sample is represented as =
Answer:
There are 5.5668 moles of water for every mole of CuSO₄.
Explanation:
The mass of anhydrous CuSO₄ is:
23.403g - 22.652g = 0.751g.
mass of crucible + lid + CuSO₄ - mass of crucible + lid
Given that the molar mass of CuSO₄ is 159.609g/mol, we calculate the moles:
0.751g × = 4.7052x10⁻³ moles CuSO₄
The mass of water in the initial sample is:
23.875g - 0.751g - 22.652g = 0.472g.
mass of crucible + lid + CuSO₄ hydrate - CuSO₄ - mass of crucible + lid
As the molar mass of H₂O is 18.02g/mol, we find the moles:
0.472g × = 2.6193x10⁻² moles H₂O
The mole ratio of H₂O to CuSO₄ is:
2.6193x10⁻² moles H₂O / 4.7052x10⁻³ moles CuSO₄ = 5.5668
This indicates there are 5.5668 moles of water per mole of CuSO₄.
I hope this is helpful!