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pashok25
1 month ago
10

Sully is riding a snowmobile on a flat, snow-covered surface with a constant velocity of 10 meters/second. The total mass of the

snowmobile, including Sully, is 280 kilograms. If Sully accelerates to a velocity of 16 meters/second over 10 seconds, what’s the force exerted by the snowmobile to accelerate? Use F = ma, where . 160 N 168 N 248 N 280 N 324 N
Physics
2 answers:
inna [3.1K]1 month ago
7 0
Result: 168N

The calculation shows 16 - 10 equals 6
and 6 divided by 10 equals 0.6
. Therefore, F equals 280 multiplied by 0.6 equals 168.
Ostrovityanka [3.2K]1 month ago
6 0
16 - 10 equals 6
and dividing 6 by 10 gives 0.6 (the sign / signifies division)
. As a result, F equals 280 times 0.6 resulting in 168.
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Answer:

The answer to the specified question will be "\mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}".

Explanation:

Referring to the question,

\sum F_{x}

⇒  TCos \theta-F_{s}=0

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\sum F_{y}

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⇒  M_{g}-TSin \theta=F_{N}...(equation 2)

Now,

From equation 1 and equation 2, we conclude

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By substituting the value of F_{N}, we derive

⇒  T_{m} Cos\theta = \mu_{s}(M_{g}-T_{m}Sin \theta)

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Thus;

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m₁ = Mass of the child

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