A child on a 2.4 kg scooter at rest throws a 2.2 kg ball. The ball is given a speed of 3.1 m/s and the child and scooter move in

La force agissant pendant 9 s et la décélération pendant 12 - 9 = 3 s.

Distance totale parcourue = 990 m

vitesse initiale u = 0

s₁ = 1/2 a 9² où a est l'accélération

vitesse finale après 9 s

v = at = 9a

pendant la décélération

v² = u² - 5 x s₂

0 = (9a)² - 5 s₂

s₂ = 16.2 a²

Distance parcourue pendant la décélération = 16.2 a²

s₁ + s₂ = 990

40.5 a + 16.2 a² = 990

16.2 a² + 40.5 a - 990 = 0

a = 6.5

Response:

The car's acceleration magnitude is 35.53 m/s²

Details:

Given;

acceleration of the truck, = 12.7 m/s²

mass of the truck, = 2490 kg

mass of the car, = 890 kg

let the acceleration of the car during the collision =

Using Newton's third law of motion;

The force exerted by the truck equals the force exerted by the car.

The car's force acts in the opposite direction.

Thus, the car's acceleration magnitude is 35.53 m/s²

Response: Numerous elements can be found, all situated within the same vertical column as bromine.

Explanation:

Elements are organized by their atomic numbers on the periodic table. Those in the same vertical column (known as groups) exhibit the same valence electron configurations, resulting in similar chemical characteristics. Consequently, there are numerous elements sharing analogous chemical properties grouped with Bromine.