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Fofino
20 days ago
6

A balloon filled with air has a volume of 4.24 liters at 23.00°

Chemistry
2 answers:
eduard [2.7K]20 days ago
7 0

pV = nRT, or V = \frac{nRT}{p}, which includes p - pressure, V - volume, n - quantity of substance, T - temperature measured in K.

Then: \frac{V_2}{V_1} = \frac{n_2RT_2p_1}{p_2n_1RT_1}

n_2 = n_1, p_2 = p_1

V_2 = V_1 \cdot \frac{T_2}{T_1} = 4.24 \frac {(273.00+5.00)}{(273.00+23.00)}=3.98 l

lions [2.9K]20 days ago
6 0

The updated volume of the balloon, when cooled at a constant pressure, is 3.98 L


Explanation

This new volume was determined using the formula from Charles' law

presented as V1/ T1 = V2/T2 where,

V1 = 4.24 L

T1= 23°C converted to kelvin = 23 + 273 = 296 K

T2 = 5.00°C converted to kelvin = 5.00 + 273 = 278 K

V2 =?


By rearranging the equation to isolate V2, we can find it by multiplying both sides by T2

V2 = V1 x T2/ T1

This results in V2 = (4.24 L x 278 K) / 296 K = 3.98 L



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Kinetic energy = 92.2 keV * (1,000 eV/1 keV) * (</span>1.602×10⁻¹⁹ joule/1 eV) = 5.76×10²³ Joules

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4 0
20 days ago
Read 2 more answers
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8 0
28 days ago
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6 0
1 month ago
The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step pr
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Response:

The pKa value is 13.0.

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Verification: The typical range for pKa in weak acids is from 2 to 13.

8 0
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