If 20.0g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

2 answers:

7 0

We know that:
<span>MgSO4.7H2O + heat = MgSO4 + 7 H2O
</span>Along with the following:
Molar mass of MgSO₄⋅7H₂O = 246.47 g/mole
Molar mass of anhydrous MgSO₄ = 120.415 g/mole

Consequently,
<span>Mass of anhydrous magnesium sulfate left over = (20 grams of MgSO₄⋅7H₂O) / (246.4746 g/mol of MgSO₄⋅7H₂O) x (1 mole of MgSO₄ / 1 mole of MgSO₄⋅7H₂O) x (120.3676 g/mol of MgSO₄)
= 7.7 grams of MgSO4</span>

KiRa [2.9K]4 months ago

5 0

Answer: 9.8g

Explanation:

This calculation assumes complete removal of water from the compound.

From there, I will determine the mass of the evaporated water and subtract that from the initial 20.0 g sample.

To do this, follow these steps:

1) Calculate the number of moles of hydrated magnesium sulfate, represented as MgSO₄⋅7H₂O

Number of moles = mass in grams / molar mass

The molar mass of MgSO₄⋅7H₂O can be calculated using the atomic masses of its constituent atoms multiplied by the number of each atom present:

Molar mass = 24.305 g/mol + 32.065 g/mol + 4×15.999g/mol + 7×2×1.008g/mol + 7×15.999 g/mol = 246.471 g/mol

Therefore, moles of MgSO₄⋅7H₂O = 20.0g / 246.471 g/mol = 0.0811 moles

2) Now calculate the number of moles of water, using the ratios derived from the chemical formula:

7 moles of H₂O / 1 mole of MgSO₄⋅7H₂O = x / 0.0811 moles of MgSO₄⋅7H₂O

⇒ x = 0.0811 × 7 moles H₂O = 0.568 moles H₂O

3) Convert moles of H₂O to grams:

Number of moles = mass in grams × molar mass = 0.568 moles × 18.015 g/mol = 10.2 g

4) Thus, the remaining mass is 20.0g - 10.2g = 9.8g

Answer;

Considering the types of bonds being created and severed in the transition state, the stability of this temporary structure is comparatively high.

Explanation;

The reaction can be expressed as follows; NO(g)+F2(g)→NOF(g)+F(g)
All chemical reactions, including exothermic ones, require activation energy to initiate. The activation energy is the least amount of energy needed for the reactants to come together, overcome opposing forces, and begin breaking bonds.
When molecules encounter each other, their kinetic energy may be sufficient to stretch, bend, and eventually break bonds, resulting in chemical reactions.

3 0

3 months ago

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)

Alekssandra [3086]

Answer:

Quantity of $H_{2}O$ generated will be reduced to fifty percent of its initial amount.

Explanation:

Equilibrium reaction: $HCl+NaOH\rightarrow NaCl+H_{2}O$

In accordance with the balanced equation, 1 mol of HCl interacts with 1 mol of NaOH leading to the formation of 1 mol of $H_{2}O$

0.5 mol of HCl interacting with 0.5 mol of NaOH yielding 0.5 mol of $H_{2}O$ .

Consequently, it is clear that the total of $H_{2}O$ produced will be halved if the quantities of the reactants are halved.

</pif>

5 0

4 months ago

At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?

castortr0y [3046]

To find the temperature at which the volume of the gas would be 0.550 L, given that it is 0.432 L at -20.0 °C, apply Charles’s Law.

The formula is v1/T1 = v2/T2
Known values:
V1 = 0.550 L
T1 = ?
T2 = -20°C + 273 = 253 K
V2 = 0.432 L

Rearranging for T1:
T1 = (V1 × T2) / V2

Calculating:
T1 = (0.55 L × 253) / 0.432 L = 322.11 K or 49.11°C

8 0

4 months ago

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