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polet
1 month ago
9

If the wire is replaced by an infinite current sheet with density Js = 0.40 A/m, what would be the magnetic flux (in T · m2) thr

ough a loop of length a = 0.27 m and width b = 0.63 m, placed a distance c = 0.10 m from the sheet? (Enter the magnitude.)
Physics
1 answer:
Sav [3.1K]1 month ago
6 0

Answer:

Clarification:\phi _{B} =0.855 T-m^{-2}

Considering the following data the density of the current sheet is 0.40 A/m

The length a = 0.27 m

and the width b = 0.63 m

For an infinite sheet, the magnetic field is described as

The magnetic flux is given as

B = \mu _{O}J

magnetic flux =

\phi _{B} = BA

                   = \mu _{O}Jab

                   = 4\pi *0.40*0.27*0.63

\phi _{B} =0.855 T-m^{-2}

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Answer:

Explanation:

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b)

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1 month ago
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1 month ago
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serg [3582]

Answer:

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A = 0.0581 m

Part b)

T = 0.37 s

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v = \sqrt{2gh}

We know that

v = \sqrt{2(9.81)(0.250)}

v = 2.21 m/s

Now applying the conservation of momentum:

mv = (m + M)v_f

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M = 0.400 kg

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0.300 (2.21) = (0.300 + 0.400) v_f

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We also determine that the speed of SHM is represented as

x_2 = 0.0343 m

Here, we derive values from

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Part b)

The time period for the scale is computed as

T = \frac{2\pi}{\omega}

T = \frac{2\pi}{16.9}

T = 0.37 s

8 0
2 months ago
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