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fenix001
4 months ago
7

When performing a flame test using the method described in the manual, you complete the flame test of KNO3 and find a yellow col

or instead of the expected purple color. Select the potential sources of error. Group of answer choices The nichrome wire is not hot enough. The solution is not concentrated enough. The flame is not optimized. The nichrome wire is dirty. The solution is contaminated. The watch glass is dirty.
Chemistry
1 answer:
Tems11 [2.7K]4 months ago
7 0

Answer:

The nichrome wire has contaminants.

The sample solution might be tainted.

Explanation:

If the nichrome wire is contaminated, sodium impurities could be causing the yellow flame. The wire is initially placed in the flame without the sample to check for such impurities.

The testing solution could also be contaminated, causing it to display a color different from the anticipated shade of the test ion.

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Montrel takes a trip to Central America during the winter. He finds out that the temperature in Central America is about the sam
lorasvet [2795]

Answer:

C

Explanation

My teacher mentioned that, for instance, Florida tends to be warm, while Central America can have both hot and cold temperatures, and a jacket isn't necessary. I don't recall many details.

6 0
3 months ago
A substance is 35.7% carbon by mass. How much carbon could be recovered from 769 g of the substance? 1. 180 mol 2. 258 mol 3. 22
KiRa [2933]

Response:

22.9 moles (Option 5)

Clarification:

A substance being 35.7% carbon by mass signifies that in every 100 g of the substance, there is 35.7 g of carbon.

Using a rule of three, we get:

100 g of substance ___ has __ 35.7 g of C

769 g of substance ___ has ___ ( 769.35.7) / 100 = 274.5 g of C

1 mol of C = 12 g/m

Mass / Molar mass = Moles

274.5 g / 12 g/m = 22.9 moles

4 0
2 months ago
Liquid nitrogen has a density of 0.807 g/ml at –195.8 °c. if 1.00 l of n2(l) is allowed to warm to 25°c at a pressure of 1.00 at
castortr0y [3046]
Step 1: Convert density from g/mL to g/L; 0.807 g/mL is equivalent to 807 g/L. Step 2: Calculate Moles of N₂; Density = Mass / Volume, or Mass = Density × Volume. Plugging in values, Mass = 807 g/L × 1 L gives us Mass = 807 g. Similarly, Moles = Mass / M.mass, which leads to Moles = 807 g / 28 g.mol⁻¹, giving us Moles = 28.82 moles. Step 3: Apply the Ideal Gas Law to determine Volume of gas occupied; P V = n R T, thus V = n R T / P. Remember to convert temperature to Kelvin (25 °C + 273 = 298 K). Hence, V = (28.82 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 298 K) ÷ 1 atm, resulting in V = 704.76 L.
8 0
3 months ago
Rank the following chemical species from lowest absolute entropy (So) (1) to highest absolute entropy (5) at 298 K?
lorasvet [2795]

Answer:

Can you rank the following chemical substances in order of their absolute entropies (So) from lowest (1) to highest (5) at a temperature of 298 K?

a. Al (s)

b. H2O (l)

c. HCN (g)

d. CH3COOH (l)

e. C2H6 (g)

Explanation:

Entropy quantifies the level of disorder within a system.

In solids, the entropy is significantly lower compared to liquids and gases.

The typical order of entropy is:

solids < liquids < gases

In the substances listed, liquid water notably exhibits strong intermolecular hydrogen bonding.

This results in water having comparatively lower entropy.

Next in line is acetic acid.

Among the gaseous components, ethane has higher entropy than HCN due to its weaker intermolecular interactions.

HCN involves some hydrogen bonding.

Thus, the order of entropy is:

Al(s) < CH3COOH (l) < H2O(l) < HCN(g) < C2H6(g)

7 0
3 months ago
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