First convert grams of C4H10 to moles using its molar mass of 58.1 g/mol:
3.50 g C4H10 × (1 mol C4H10 / 58.1 g C4H10) = 0.06024 mol C4H10
Next convert moles to molecules using Avogadro’s number:
0.06024 mol C4H10 × (6.022×10^23 molecules C4H10 / 1 mol C4H10) = 3.627×10^22 molecules C4H10
Each butane molecule contains 4 carbon atoms, so:
3.627×10^22 molecules C4H10 × (4 atoms C / 1 molecule C4H10) = 1.45×10^23 carbon atoms present.
Answer:
Explanation:
The oxidation state corresponds to the charge of each atomic ion. An increase indicates oxidation of the element while a decrease reflects reduction of the element.
2AgCl+Zn⟶2Ag+ZnCl2
Zinc undergoes oxidation, while Ag experiences reduction.
Ag⁺ changes to Ag (oxidation state decreases), thus Ag is reduced.
Zn alters to Zn⁺² (oxidation state increases), hence Zn is oxidized.
4NH₃+3O₂⟶2N₂+6H₂O
The oxidation state of nitrogen in ammonia is -3
whereas it is zero in elemental nitrogen.
An increase in the oxidation state indicates nitrogen is oxidized.
The oxidation state of oxygen is zero when in molecular oxygen and -2 when in water. Therefore, the oxidation state decreases, indicating oxidation is reduced.
Fe₂O₃+2Al⟶Al₂O₃+2Fe
The oxidation state of Fe in Fe₂O₃ is +3, switching to zero in Fe, so iron is reduced.
Aluminum's oxidation state is zero in Al, rising to +3 in Al₂O₃, indicating it is oxidized.
The correct answer is the fifth option. Energy transfers from the fire to the pot, subsequently to the water, and then to the peas.
Response: 670K
Rationale:
Provided data includes:
Initial volume of gas V1 = 1.22 L
Initial temperature T1 = 286 K
Final volume V2 = 2.86 L
Final temperature T2 =?
As temperature and volume are interrelated when pressure remains constant, apply Charles' law:
V1/T1 = V2/T2
1.22 L/286 K = 2.86 L/ T2
Cross multiplication yields:
1.22 L x T2 = 286 K x 2.86 L
1.22T2 = 817.96
Solving for T2:
1.22T2/1.22 = 817.96/1.22
T2 = 670.459 K (rounded to the nearest whole number is 670 K)
Therefore, the gas temperature is 670 Kelvin
