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Paladinen
1 month ago
12

modern vacuum techniques make it possible to reach a pressure of 1.00 * 10 ^ -10 mm Hg in a laboratory system. what volume in mi

lliliters would 1.00 * 10 ^ 6 molecules of gas occupy at this pressure and standard temp?​
Chemistry
1 answer:
lorasvet [2.7K]1 month ago
5 0
At a pressure of 1.00 × 10⁻¹⁰ mmHg and a temperature of 273.15 K, the volume occupied by the 1.00 × 10⁶ moles of gas is 1.70 × 10²³ millilitres. This is derived from the universal gas equation PV = nRT, where V is the volume, n is the number of moles (1.00 × 10⁶), R is the universal gas constant (62.363 mmHg·L/(mol·K)), T is the temperature (273.15 K), and P is the pressure (1.00 × 10⁻¹⁰ mmHg). By substituting these values into the equation, we find the volume in millilitres equals 1.703 × 10²⁰ L converted to millilitres equals 1.703 × 10²³ millilitres.
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Which statement is TRUE regarding the macroscopic and
lions [2927]

Answer:

Chemists observe phenomena on a macroscopic level which informs their understanding of microscopic aspects.

Explanation:

Many critical chemical insights arise from macroscopic observations because most scientific instruments currently cannot directly evidence microscopic events. Data gathered from these larger-scale observations can yield valuable insights into the nature of specific microscopic interactions.

This is particularly true in atomic structure studies. The majority of evidence that contributed to our understanding of atomic structure was obtained from macroscopic observations and subsequently provided crucial information regarding the atom's microscopic configuration.

7 0
2 months ago
Determine the number of bonding electrons and the number of nonbonding electrons in the structure of xef2. enter the number of b
KiRa [2933]

Result: The count of bonding electrons and non-bonding electrons amounts to (4, 18).

Explanation:

The Lewis-dot structure reveals the number of bonding and non-bonding electrons in XeF_2.

Lewis-dot representation: It illustrates the valence electron count for atoms in a molecule and shows how they bond, as well as any lone pairs of electrons.

In this structure, 'Xe' is the central atom while 'F' is the terminal atom.

Xenon comprises 8 valence electrons, whereas fluorine contains 7.

The total number of valence electrons in XeF_2 is calculated as 8 + 2(7) = 22 electrons

From the Lewis-dot structure, we can determine

The count of electrons involved in bonding = 4

The count of electrons involved in non-bonding (lone-pairs) = 22 - 4 = 18

Thus, the bonding and non-bonding electron counts are (4, 18).

Below is the Lewis-dot structure for XeF_2.

4 0
1 month ago
Read 2 more answers
Find the molarity of 750 ml solution containing 346 g of potassium nitrate
lorasvet [2795]
For KNO₃, the mass is 346g. The molar mass can be computed as (39.098) + (14) + (15.99*3), which results in 101.068 gmol⁻¹. The volume of the solution is given as 750ml, equivalent to 0.75dm³. The formula for molarity is (mass of solute/molar mass of solute)*(1/volume of solution in dm³). Accordingly, molarity = (346/101.068)*(1/0.75), yielding 4.56 mol dm⁻³.
5 0
1 month ago
What mass of calcium carbonate (in grams) can be dissolved by 4.0 g of hcl? (hint: begin by writing a balanced equation for the
Alekssandra [3086]
The interaction between calcium carbonate and hydrochloric acid can be represented by the chemical equation,

    CaCO3 + 2HCl --> CaCl2 + H2O + CO2

Calcium carbonate has a molecular weight of 100 g/mol, while hydrochloric acid's molecular weight is 36.45 g/mol. According to the equation, 100 g of calcium carbonate reacts with 72.9 g of hydrochloric acid.

    x = (4 g HCl)(100 g CaCO3 / 72.9 HCl)
      x = 5.49 g

Final result: 5.49 g
8 0
2 months ago
Read 2 more answers
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