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Paladinen
2 days ago
12

modern vacuum techniques make it possible to reach a pressure of 1.00 * 10 ^ -10 mm Hg in a laboratory system. what volume in mi

lliliters would 1.00 * 10 ^ 6 molecules of gas occupy at this pressure and standard temp?​
Chemistry
1 answer:
lorasvet [2.5K]2 days ago
5 0
At a pressure of 1.00 × 10⁻¹⁰ mmHg and a temperature of 273.15 K, the volume occupied by the 1.00 × 10⁶ moles of gas is 1.70 × 10²³ millilitres. This is derived from the universal gas equation PV = nRT, where V is the volume, n is the number of moles (1.00 × 10⁶), R is the universal gas constant (62.363 mmHg·L/(mol·K)), T is the temperature (273.15 K), and P is the pressure (1.00 × 10⁻¹⁰ mmHg). By substituting these values into the equation, we find the volume in millilitres equals 1.703 × 10²⁰ L converted to millilitres equals 1.703 × 10²³ millilitres.
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The answer is C. The specific amount of energy released when excited electrons fall back to the ground state produces an emission spectrum. That energy is emitted as photons with precise wavelengths corresponding to the energy differences between levels. Because each element yields a characteristic set of wavelengths, the emission spectrum can be used to identify the element in the sample.
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13 days ago
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Which statement is correct? Salts are formed by the reaction of bases with water. Most salts are ionic and are soluble in water.
lorasvet [2504]
<span>Salts result from the reaction between bases and water. - FALSE
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1 month ago
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At the boiling point, the density of the liquid is 809 g/l and that of the gas is 4.566 g/l. how many liters of liquid nitrogen
KiRa [2687]

Result: 1.68 L of liquid nitrogen is generated during the gas liquefaction process.

Clarification:

This process involves transforming gaseous nitrogen into its liquid form.

The two states possess distinct densities, thus occupying varying volumes; however, the mass remains constant.

Step 1: Calculate the mass of nitrogen gas

Let’s determine the mass of nitrogen gas associated with 297 L.

The density formula is:

Density = \frac{Mass}{Volume}

With a density of nitrogen gas at 4.566 g/L and a volume of 297 L, we can compute the mass of nitrogen gas as follows:

Using these values yields:

Mass = Density \times Volume

Mass = \frac{4.566g}{L} \times 297L

Mass = 1356g

The mass of nitrogen gas calculates to be 1356 g.

Step 2: Derive the volume of liquid nitrogen from the mass obtained

The mass for liquid nitrogen remains the same.

With the density of liquid nitrogen at 809 g/L, we can substitute this into our formula to find the volume of liquid.

Volume = \frac{Mass}{Density}

Volume = \frac{1356g}{809g/L}

Therefore, the volume of liquid nitrogen is 1.68 L.


6 0
1 month ago
Blood is composed of many tiny cells in a liquid called plasma. Blood is actually considered a colloid. The dispersed state of m
VMariaS [2675]

Answer:

In blood: Dispersed phase: blood cells; Dispersed medium: liquid plasma

In fruit jelly: Dispersed phase: fruit juice; Dispersed medium: pectin

Explanation:

The dispersed phase refers to the phase where colloidal particles are dispersed within another phase, known as the dispersion medium.

In blood, the tiny cells act as colloidal particles, forming the dispersed phase within the liquid medium identified as plasma.

Conversely, in fruit jelly, the fruit juice constitutes the dispersed phase while the solid pectin serves as the dispersed medium.

4 0
9 days ago
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What acid chloride would be needed to prepare the following ketone from benzene using a Friedel-Crafts acylation? Click the "dra
alisha [2704]

Answer:

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Explanation:

                     Friedel-Craft Acylation is a reaction used to incorporate electrophiles (especially carbonyl groups) into the double bonds of aromatic compounds.

This scenario involves synthesizing benzophenone using benzene and benzoyl chloride.

Mechanism:

Step 1: Initially, benzoyl chloride reacts with a Lewis acid to create an electrophile known as oxo(phenyl)methylium.

Step 2: The second stage involves benzene participating in an electrophilic substitution reaction, where the electrophile is added.

Step 3: Finally, the aromatic nature of benzene is restored by releasing a proton.

3 0
27 days ago
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