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iris
2 months ago
13

The combustion of propane (c3h8) produces co2 and h2o: c3h8 (g) + 5o2 (g) → 3co2 (g) + 4h2o (g) the reaction of 2.5 mol of o2 wi

th 4.6 mol of c3h8 will produce ________ mol of h2o.
Chemistry
1 answer:
Anarel [2.9K]2 months ago
8 0
The reaction will yield 2 mol of H₂O. The balanced chemical equation for this process is: c3h8 (g) + 5o2 (g) → 3co2 (g) + 4h2o (g). Since 5 moles of O₂ create 4 moles of H₂O, 2.5 mol of O₂ will produce: 2.5 x 4/5 = 2 mol of H₂O.
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Select the word or phrase from the drop-down menu to describe ionic compounds. A formula unit represents the simplest ratio of e
VMariaS [2998]

Response:

CRYSTAL

A LARGE NUMBER OF ATOMS ORGANIZED IN A REGULAR STRUCTURE

1:1

Reasoning:

8 0
2 months ago
Read 2 more answers
How many electrons are involved in one equivalent of oxidation-reduction?
Alekssandra [3086]
One electron is involved. Explanation: In redox reactions, determining the equivalents requires knowledge of the number of transferred electrons. In this specific case, one equivalent corresponds to a transfer of a single electron.
3 0
2 months ago
Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d
KiRa [2933]

Response: k = 23045 N/m

Clarification:

To determine the spring constant, one must consider the maximum elastic potential energy that the spring can withstand. The kinetic energy of the vehicle should equal at minimum the elastic potential energy of the spring when it is fully compressed. Hence, we express it as:

K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2    (1)

M: mass of the vehicle = 1050 kg

k: spring constant =?

v: car speed = 8 km/h

x: maximum spring compression = 1.5 cm = 0.015m

You need to resolve equation (1) for k. Beforehand, convert the speed v to meters per second:

v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}

k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}

The spring constant calculates to 23045 N/m

3 0
2 months ago
his is the chemical formula for chromium(III) nitrate: . Calculate the mass percent of oxygen in chromium(III) nitrate. Round yo
eduard [2782]

Answer:

\%\ Composition\ of\ iron=69.92\ \%

Explanation:

The percent composition indicates the mass percentage of a specific element within the compound.

The chemical formula for chromium(III) nitrate is Cr(NO_3)_3.

The molar mass for chromium(III) nitrate is calculated at 238.011 g/mol.

Each mole of chromium(III) nitrate includes 9 moles of oxygen.

The molar mass of oxygen is 16 g/mol.

Hence, Mass = Molar mass * Moles = 16 * 9 g = 144 g.

\%\ Composition\ of\ iron=\frac{Mass_{iron}}{Total\ mass}\times 100

\%\ Composition\ of\ iron=\frac{144}{238.011}\times 100

\%\ Composition\ of\ iron=69.92\ \%

5 0
2 months ago
Calculate the grams of oxygen in 90.0 g of cl2o
lorasvet [2795]
To find the mass of oxygen in the specified compound, we require the molar mass for both the compound and oxygen. We also establish the relationship between the number of moles of oxygen per mole of the substance. The calculation proceeds as follows:

90.0 g ( 1 mol / 86.91 g ) ( 1mol O / 1 mol Cl2O) ( 16 g / 1 mol ) = 16.57 g O


4 0
2 months ago
Read 2 more answers
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