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Slav-nsk
1 month ago
6

A flask contains 0.25 mole of SO2(g), 0.50 mole of CH4(g), and 0.50 mole of O2(g). The total pressure of the gases in the flask

is 800 mm Hg. What is the partial pressure of the SO2(g) in the flask?
Chemistry
1 answer:
castortr0y [3K]1 month ago
4 0
The flask contains a partial pressure of sulfur dioxide gas measured at 160 mmHg. We have the following information: Moles of sulfur dioxide gas = 0.25 moles, Moles of methane gas = 0.50 moles, Moles of oxygen gas = 0.50 moles. To determine the mole fraction of sulfur dioxide, we utilize the following law: The partial pressure of a gas can be calculated using Raoult's law: where, = the partial pressure of sulfur dioxide, = total pressure = 800 mmHg, = mole fraction of sulfur dioxide = 0.2. Substituting the values into this equation results in: Therefore, the partial pressure of sulfur dioxide gas in the flask stands at 160 mmHg.
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VMariaS [2998]

Response:

Examine the explanation

Explanation:

In this scenario, Nitrogen (N) experiences oxidation while Chlorine (Cl) undergoes reduction.

In response to your inquiry:

N is oxidized from an oxidation state of -3 to -1.

Cl is reduced from an oxidation state of +1 to -1.

At this point,

Borneol will likely exhibit a lower Rf due to its boiling point.

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How would a flood be a limitation for synthetic polymers that rely on natural rubber in its production?
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3 0
2 months ago
Read 2 more answers
When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq), 3.14 kJ of heat are produced. Determine the enthalpy change per mole o
Alekssandra [3086]

Answer: The change in enthalpy for each mole of zinc involved in the reaction is 152.4 kJ/mol.

Explanation:

First, we need to determine the moles of Zn and HCl.

\text{Moles of }Zn=\frac{\text{Mass of }Zn}{\text{Molar mass of }Zn}

The molar mass of Zn is 65 g/mole

\text{Moles of }Zn=\frac{1.34g}{65g/mole}=0.0206mole

and,

\text{Moles of }HCl=\text{Concentration of }HCl\times \text{Volume of solution}=0.750M\times 0.0600=0.0450mole

Next, we must identify the limiting reagent and the excess reagent.

The chemical reaction given is:

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

According to the balanced reaction we find that

1 mole of Zn reacts with 2 moles of HCl

Thus, 0.0206 moles of Zn react with 0.0206\times 2=0.0412 moles of HCl

This leads us to determine that HCl is the excess reagent because the moles provided exceed the required moles, while Zn is limiting and restricts product formation.

Now to find the enthalpy change for each mole of zinc reacting in this reaction.

From the reaction we gather that,[ [TAG_59]]

0.0206 moles of Zn yield heat = 3.14 kJ

This implies that 1 mole of Zn generates heat = \frac{3.14kJ}{0.0206mol}=152.4kJ/mol

Hence, the enthalpy change per mole of zinc involved in this reaction amounts to 152.4 kJ/mol.

5 0
2 months ago
Calculate the number of C atoms in 9.837 x 1024 molecules of CO2. <br><br>Please help
alisha [2963]

Response:

Each molecule consists of one carbon atom.

9.837 * 10^24 molecules correspond to 9.837 * 10^24 carbon atoms.

It's a 1:1 relationship.

6 0
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