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Rom4ik
2 months ago
7

An automobile is traveling at a constant 15 m/s, then it undergoes acceleration from that moment forward. Which statement best d

escribes the automobile's new motion?​
Physics
1 answer:
ValentinkaMS [3.4K]2 months ago
7 0

Answer:

d

Explanation:

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One day you are driving your friends around town and you drive quickly around a corner without slowing down. You are going at a
Ostrovityanka [3204]

Result:

1.60 g

Elucidation:

Based on the attached document:

we can infer that:

v = v_x =v_y = 20 \ m/s \\t = 2s

The distance covered in 2 seconds will be:

x = vt

x = 20 m/s × 2 s

x = 40 m

The segment corresponds to a quarter of a circle with radius r,

therefore, if 2 πr = 4 x

Then the radius (r) can be calculated as:

r = \frac{4x}{2 \pi}\\\\r = \frac{4*40}{2 \pi}

r = 25.5 m

Centripetal acceleration can be expressed as:

a = \frac{v^2}{r}

thus;

a = \frac{(20 \ m/s^2)}{25.5 \ m}

a = 15.7 m/s²

The acceleration magnitude suffered by your passengers in relation to the acceleration due to gravity can be calculated using:

a' = \frac{a}{g} g

a' = \frac{15.7 \m/s ^2}{9.81 \ m/s^2}\ g

a' = 1.60 \ g

∴ The acceleration magnitude experienced by your passengers while turning = 1.60 g

6 0
1 month ago
Read 2 more answers
You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves along a frictionless track. however, af
serg [3582]
I’ve provided the missing image. We can analyze this scenario by applying the principle of energy conservation. At point A, the car possesses both potential and kinetic energy. As it moves down the track, some initial energy is lost due to friction. Thus, as it approaches point B, we have a specific amount of energy remaining. According to the conservation of energy laws, this remaining energy at point B will equal the sum of its kinetic and potential energy.
4 0
1 month ago
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Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer
inna [3103]

The peak wavelength for Betelgeuse is 828 nm

Explanation:

Wien's law describes how the surface temperature relates to a star’s peak wavelength:

\lambda=\frac{b}{T}

where

\lambda represents the peak wavelength

T is the surface temperature

b=2.898\cdot 10^{-3} m\cdot Kis Wien's constant

For Betelgeuse, the surface temperature is roughly

T = 3500 K

Consequently, its peak wavelength can be determined as:

\lambda=\frac{2.898\cdot 10^{-3}}{3500}=8.28\cdot 10^{-7} m = 828 nm

Learn more about wavelength:

8 0
1 month ago
myron is almost late for class and he is running quickly to arrive before the professor begins lecturing as he listen to the pro
inna [3103]
No established theory exists here.
Myron has presented a strong hypothesis to clarify his observations.
Alternative hypotheses could be:

-- An infected mosquito might have bitten him during his sleep, causing symptoms to manifest.

-- He may have consumed something for dinner that was a bit spoiled.

-- He might have had excessive alcohol at the fraternity party last night.

-- The air in the classroom could contain elevated levels of Carbon Dioxide.

-- His body might be responding to the physical exertion of rushing to class.

Currently, Myron has merely formulated a hypothesis.
He cannot draw any "conclusion" until he tests his hypothesis and demonstrates that similar outcomes consistently result from the same conditions. Testing his hypothesis may prove challenging, but unless he does so, he lacks a comprehensive theory.

In my view, while his hypothesis may indeed be valid, the most probable explanation for his experience is the recent physical strain from running to class. It’s crucial to note that I cannot convince anyone of this conclusion; my perspective is merely another hypothesis. Its validity holds no significance unless it undergoes testing.
6 0
1 month ago
An end of a light wire rod is bent into a hoop of radius r. The straight part of the rod has length l; a ball of mass M is attac
ValentinkaMS [3465]

Answer:

arcsin(\frac{R\mu}{(R+l)\sqrt{\mu^2+1}})

Explanation:

By applying the Law of Sines,

sin \theta = \frac{sin \phi R}{ l + R}

Based on Newton's Law,

mg = N\sqrt{\mu^2+1}

And the final equation also derived from Newton's Law,

\mu N = mgsin\phi

Then by consolidating all the equations together,

\mu N = mgsin\phi = N\sqrt{\mu^2+1}sin\phi\\

sin\theta = \frac{\mu R}{ (l + R)\sqrt{\mu^2+1}}

Thus,

\theta = arcsin(\frac{R\mu}{(R+l)\sqrt{\mu^2+1}})

8 0
14 days ago
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