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Alina
2 months ago
13

Compared to a 26-gram sample of NaCl(s) at STP, a 52-gram sample of NaCl(s) at STP has(1) a different density(2) a different gra

m-formula mass(3) the same chemical properties(4) the same volume
Chemistry
1 answer:
KiRa [2.9K]2 months ago
6 0
Choice (3) is correct: they exhibit the same chemical properties. Both samples are under identical conditions, so their densities remain unchanged. Gram-formula mass is an intrinsic property of the substance and does not vary. The volume would change if the mass changes.
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3,048 minutes. Explanation: 762 divided by 5, then multiply that number by 20.
5 0
2 months ago
An experimental drug, D, is known to decompose in the blood stream. Tripling the concentration of the drug increases the decompo
lions [2927]

Answer:

The rate law for the decomposition reaction is:

R=k[D]^2

The unit for the rate constant will be M^{-1}s^{-1}

Explanation:

D\rightarrow Product

The rate law can be expressed as:

R=k[D]^x..[1]

When the drug concentration is tripled, the decomposition rate rises by a factor of nine.

[D]'=3[D]

R'=9\times R

R'=k[D]'^x...[2]

[1] ÷ [2]

\frac{R}{R'}=\frac{k[D]^x}{k[D']^x}

\frac{R}{9R}=\frac{k[D]^x}{k[3D]^x}

9=3^x

Solving for x results in:

x = 2.

This indicates a second-order reaction.

The decomposition reaction's rate law is:

R=k[D]^2

The unit for the rate constant will be:

k=\frac{R}{[D]^2}=\frac{M/s}{(M)^2}=M^{-1}s^{-1}

The unit for the rate constant will be M^{-1}s^{-1}.

5 0
3 months ago
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