Compared to a 26-gram sample of NaCl(s) at STP, a 52-gram sample of NaCl(s) at STP has(1) a different density(2) a different gra

Response:

The accurate choice is;

Sulfur oxides linked to acid precipitation

Details:

Sulfur oxide in the atmosphere interacts with oxygen, water, and other chemicals leading to the creation of acidic precipitation known as acid rain.

Sulfur oxides react with moisture in clouds to generate sulfuric acid as follows;

The sulfur gas undergoes initial oxidation

SO₂ + OH → HOSO₂

The subsequent step involves producing sulfur trioxide

HOSO₂ + O₂ → HO₂ + SO₃

Finally, sulfur trioxide reacts with water to yield sulfuric acid

SO₃ + H₂O → H₂SO₄ (aq).

Answer: These celestial bodies are composed of rock or gas and are named after ancient deities.

Explanation:

Earth is the THIRD planet from the Sun and is capable of sustaining life for various organisms.

VENUS ranks as the second planet in our solar system and derives its name from the Roman goddess associated with love and beauty.

MARS, the fourth planet, gets its name from the Roman goddess of war.

Hence, Venus and Mars are NEIGHBORS to EARTH.

Explanation: In ozonolysis (where a reducing agent like Zn is involved during hydrolysis), a pi bond cleaves to generate ketones or aldehydes.

Ketones arise from the double bond's disubstituted side, whereas aldehydes come from the monosubstituted side of the same bond.

Notably, ozonolysis comprises two steps: (1) the formation of an ozonide, followed by (2) the hydrolysis of the ozonide.

Hydrolysis can transpire with or without a reducing agent. When it occurs without a reducing agent, carboxylic acid, carbon dioxide, or ketones can be produced.

In this case, 2,4,4-trimethyl-2-pentene yields a mixture of and

The reaction process is illustrated below.

Answer: The mole fraction of nitrogen is calculated to be 0.4615.

Explanation: In the mixture of nitrogen () and hydrogen (), the mole ratio established is 1: 1.5.

At this juncture, we identify that () serves as the limiting reagent.

When 0.4 moles of () are produced, it will require 0.4 moles of () along with 3.4 moles of ().

The total amount of remaining () ends up being 0.6, while the amount of () left in the mixture is 0.3 moles.

The mole fraction of () is computed as 0.6 divided by the sum of 0.6, 0.4, and 0.3, resulting in 0.4615.