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Dimas
11 days ago
13

What is the mass in grams of KBr in 0.400 L of a 0.350 M solution???

Chemistry
2 answers:
Anarel [2.9K]11 days ago
8 0
The mass of KBr required is 16.7 g. This concludes from a volume of 0.400 L and a concentration of 0.350 M. Utilizing the molarity formula, moles are calculated as 0.14, leading to a molecular weight calculation of 119 g/mol, thus resulting in a mass of 16.7 g of KBr.
Anarel [2.9K]11 days ago
6 0
The mass computed for KBr in 0.400 L of a 0.350 M solution amounts to 16.7 g.
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How many moles of chromium metal equal 7.52 × 1022 atoms Cr?
Alekssandra [3086]

Response:

0.125 moles

Explanation:

According to Avogadro's principle, one mole of any substance contains 6.02x10^23 atoms.

This implies that 1 mole of chromium consists of 6.02x10^23 atoms.

Therefore, if 1 mole of chromium corresponds to 6.02x10^23 atoms,

Then X moles of chromium are equivalent to 7.52x10^22 atoms, thus

X moles of chromium = 7.52x10^22/6.02x10^23

Thus, X moles of chromium = 0.125 moles

Consequently, 0.125 moles of chromium contain 7.52x10^22 atoms

8 0
24 days ago
A piece of iron (C=0.449 J/g°C) and a piece of gold (C=0.128 J/g°C) have identical masses. If the iron has an initial temperatur
lorasvet [2795]
The true statement is B. With identical masses for both metals, the final temperature of the two will be more aligned with 498 K rather than 298 K, as iron's specific heat capacity is significantly greater than that of gold's.
4 0
1 month ago
4. Which of the following statements correctly describe atoms? Select all that apply.
castortr0y [3046]

Answer:

A, B, and C

Explanation:

Indeed, atoms possess mass and serve as the fundamental building blocks of chemical elements. While matter is composed of atoms, these particles themselves do not occupy physical space.

Atoms consist mostly of void, which excludes them from the other responses.

This confirms that A, B, and C are the right choices.

6 0
1 month ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
VMariaS [2998]

Answer:

The heat capacity of the calorimeter is C_c = 54.4 \frac{J}{c}

Explanation:

Given the data

Heat supplied Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Change in temperature = ΔT = 35.82 - 24.58 = 11.24 °C

From the conditions provided

Q = m_w C_w ΔT + C_c ΔT

Plugging all values into the above equation yields

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This represents the heat capacity of the calorimeter.

7 0
1 month ago
Calculate the ratio of the velocity of helium atoms to the velocity of neon atoms at the same temperature.
Tems11 [2777]

Answer:

vHe / vNe = 2.24

Explanation:

To determine the velocity of an ideal gas, one should apply the formula:

v = √3RT / √M

In this equation, R represents the gas constant (8.314 kgm²/s²molK); T refers to temperature, and M indicates the molar mass of the gas (4x10⁻³kg/mol for helium and 20.18x10⁻³ kg/mol for neon). Hence:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

The ratio simplifies to:

vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol

vHe / vNe = 2.24

I hope it assists you!

8 0
1 month ago
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