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devlian
10 days ago
5

Claire is investigating potential and kinetic energy using a large ball. For her investigation, Claire will stand at the top of

a hill and push the ball down the hill. The picture shows Claire's investigation
How will the ball's potential and kinetic energy change as it rolls down the hill?
Group of answer choices

The ball's potential energy will increase, and its kinetic energy will decrease.

The ball's potential energy will decrease, and its kinetic energy will increase.

The ball's potential and kinetic energy will both decrease.

The ball's potential and kinetic energy will both increase.

Chemistry
1 answer:
alisha [2.8K]10 days ago
3 0
As the ball descends down the hill, its potential energy diminishes while its kinetic energy rises.

The ball's potential energy will decrease as it moves down the slope, and its kinetic energy will experience an increase.

Kinetic energy refers to the energy possessed by an object in motion.

K. E = \frac{1}{2} m v²

where m is the mass of the ball

and v represents the ball's velocity.

Potential energy is the energy associated with an object's position as it traverses down a slope, expressed as:

P.E = mgh

with m as the mass of the ball,

g as gravitational acceleration, and h as the height.

It is clear that as the object descends, its height decreases, while its velocity increases.

learn more:

Potential energy

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In KCI how are the valence electrons distributed
eduard [2645]

Answer:

Explanation:

In KCl, the two elements that combine to create KCl are potassium (K) and chlorine (Cl).

Potassium, as a Group 1 element, possesses one valence electron in its outermost shell which it readily donates during bonding. Every element aims to achieve a stable electron configuration, typically with 2 or 8 electrons in its outer shell. Potassium is characterized by its lower electronegativity and higher ionization energy, making it more likely to donate its electron than to accept one. On the other hand, chlorine belongs to Group 17 and has 7 electrons in its outer shell, requiring just one additional electron to complete its octet. Chlorine’s higher electronegativity and lower ionization energy facilitate its tendency to accept an electron rather than donate it.

The bond between potassium and chlorine that results in KCl is termed an electrovalent bond.

Reaction equation:

K + Cl → KCl

3 0
1 month ago
Calculate the number of grams of carbon dioxide produced from complete combustion of one liter of octane by placing the conversi
Tems11 [2631]

Answer:

15.71g

Explanation:

The combustion equation that applies to hydrocarbons is

CxHy + (x+y/4) O2 = xCO2 + (y/2) H2O

In the case of octane, C8H18:

C8H18 + ( 8 + 18/4 ) O2 = 8CO2 + 9H2O

C8H18 + 50/4 O2 = 8CO2 + 9H2O

C8H18 + 25/2 O2 = 8CO2 + 9H2O

2C8H18 + 25 O2 = 16 CO2 + 18H2O (this is the balanced equation)

From this balanced reaction,

2 x 22.4 L of octane generates 16 [ 12 + (16 x 2)] of carbon dioxide

That means,

44.8 L of octane generates 704g of carbon dioxide

Thus, for 1L of octane, it produces 1 L x 704g/44.8 L = 15.71g of carbon dioxide

Consequently, 15.71g of carbon dioxide is produced from the complete combustion of 1 L of octane.

7 0
1 month ago
At –45oC, 71 g of fluorine gas take up 6843 mL of space. What is the pressure of the gas, in kPa?
KiRa [2857]
The quantity of fluorine in moles is calculated as 71/19 = 3.74
We also know that at standard temperature and pressure (273 K and 101.3 kPa), one mole of gas occupies 22.4 liters
So, the volume for 3.74 moles at S.T.P is: 3.74 x 22.4
This results in a volume of 83.776 L, which is equivalent to 83,776 mL

Next, applying Boyle's law, which states that for a fixed amount of gas,
PV = constant

We set up the equation P x 6843 = 101.3 x 83776
Solving for P gives us 1,240 kPa
4 0
20 days ago
Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) c
KiRa [2857]

Answer:

[Cl⁻] = 0.016M

Explanation:

To begin, we analyze the reaction:

Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓  +  Mg(NO₃)₂(aq)

This indicates a solubility equilibrium, resulting in the formation of lead(II) chloride precipitate. The salt can dissociate as follows:

           PbCl₂(s)  ⇄  Pb²⁺ (aq)  +  2Cl⁻ (aq)     Kps

Initial        x

React       s

Eq          x - s              s                  2s

Given that this is an equilibrium scenario, the Kps serves as the constant (Solubility product):

Kps = s. (2s)²

Kps = 4s³ = 1.7ₓ10⁻⁵

4s³ = 1.7ₓ10⁻⁵

s =  ∛(1.7ₓ10⁻⁵. 1/4)

s = 0.016 M

3 0
1 month ago
What salt is produced from mixing csoh and h2co3
Anarel [2728]

Answer:

The resulting salt is Cesium Carbonate

Explanation:

2CsOH + H2CO3 → Cs2CO3 + 2H2O

3 0
13 days ago
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