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18 days ago

Helen draws a random circle.

Mathematics

1 answer:

Leona [9.2K]18 days ago

7 0

Answer:

Upper limit: 3.116

Lower limit: 3.125

Step-by-step breakdown:

The random circle drawn by Hellen has a circumference of C=405 mm, measured to 3 significant figures, leading to a diameter, d, of 130 mm, accurate to 2 significant figures.

We utilize the formula

$\pi = \frac{C}{d}$

Substituting in the figures provides:

$\pi = \frac{405}{130}$

$\pi = 3.11538461538$

Consequently, Hellen’s value for π is recorded as 3.115 to three decimal places.

To find both limits, we divide the specified level of precision by two.

$\frac{0.001}{2} = 0.0005$

This figure is then added to the rounded number to determine the upper limit:

3.115+0.0005=3.1155

The lower limit calculates as 3.115-0.0005=3.1145

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I have provided the graphs for the functions f(x) (depicted in blue) and g(x) (depicted in red) in the attached PDF file.

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If ef bisects angle ceb,angle cef=7x+31 and angle feb=10x-3

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Given: The angle < CEB is divided by EF.

< CEF = 7x +31.

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We will find the values of x and the measures of < FEB, < CEF, and < CEB.

Solution: The angle < CEB is divided into two angles < FEB and < CEF.

Therefore, < FEB is equal to < CEF.

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